Answer:
<em>π∫52(ey3)2dy</em>
The work I did to solve this equation:
Step 1
<em>ln(3x)=2
</em>
<em>3x=2e
</em>
<em>x=2e3
</em>
Step 2
<em>ln(3x)=5
</em>
<em>3x=5e
</em>
<em>x=5e3</em>
Step 3
<em>y=ln(3x)⟺ey=3x⟺ey3=x</em>
Step 4
π∫52(ey3)2dy
3x+5y=9 3x+5y=9
-1(3x+2y=3) -3x-2y=-3
3y=6
y=2
3x+5(2)=9
3x+10=9
-10 -10
3x=-1
x=-1/3 (-1/3,2)
The answer is A. A^2+b^2=c^2
The answer is 3.7a+3b
Because you combine like terms
Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
