Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
Follow the order of operations. PEMDAS. Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. Let's start with parenthesis. First we so everything inside the parenthesis. So the first thing we do, is exponents, 2 x 2 = 4. Now the top equation is 3 x 4 - 23. Next thing in the order of operations, is Multiplication. So now we do 3 x 4. Which equals 12. Now the top equation is 10 - 12 - 23. Now we do Subtraction in order. First 10 - 12 = negative 2 (-2) Then we do -2 - 23 which equals negative 25 (-25). Now let's work on the bottom equation. Once again follow the order of operations. We do the exponents in the parenthesis first. 10 x 10 = 100. Then do the rest in the parenthesis, 1 + 100 = 101. Now the exponents in the outside of the parenthesis. - 2 x - 2 = 4. And 5 x 5 = 25. Then we do Multiplication, 4 x 25, which equals 100. Then we do 101 - 100 = 1. Then we reduce the fraction. -25/1 = -25. Therefore the answer to your problem is -25. I apologize for taking so long to write this. Hope this helps though!
-Twixx
Take -5x + 3x = -2x
because there is a -3x and a 3x they cancel each other out.
and the -17 is left
-2x = -17
divide -2 by -17 = 8.5
1/4
since there is 4 letters in the word math
so 1 out of 4
<em>Hope it helps...</em>
