A counterexample for the statement 'All square roots are irrational numbers.' is the square root of 9. This is because when simplified, the answer is 3.
For a number to be irrational, it can't be expressed in fractional form. However, 3 can be expressed in fractional form as 3/1.
The equations give you information as to where to plot points.
For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.
For y = -2x + 4, the slope is -2 (so it will also slope downwards), and the y-intercept is 4. Find (0, 4) and plot it. The -2 tells you to count 2 units down (instead of 1 like we did for the last equation) and 1 over. That is the second line.
I hope this helps.
Step-by-step explanation:
1. we have to write the system specifications as:
A(x,y) give us the meaning that the consule x can be accessed when y is in a faulty condition
∀y∃A(x,y)
2. B(x,y) shows that users email has sent a message, y. Which is in the archive. C(x) shows the email address of user x is retrievable
∀x∃y[B(x,y)→c(x)]
3. D(x,y) shows that x can detect breach y'' and we have E(z) that tells us there is a compromise of z
∀y∃xD(x,y)↔ ∃zE(z)
4. F(x,y,z)
Y and z are distinct point ends which x connects
We have,
∀y∀z∃x∃a[x ≠a →F(x,y,z)^F(a,y,z)
5. G(x,y)
X knowst the password of y' and H(x) means that we have x to be a system administrator
∀x[H(x)→∀yG(x,y)] ∃x[H(x)^∀yG(x,y)]
We can solve this by substitution
-2x=6-6y
-2x/-2=(6-6y)/-2
x= -3+3y
7(-3+3y)+8y=-6
-21+21y+8y=-6
29y=15
y=15/29
-2x+6(15/29)=6
-2x+90/29=6
-2x=6-90/29
-2x= 174/29-90/29
-2x= 84/29
-2x(29)=(84/29)29
-54x=84
x= -84/54
x= -14/9
so x= -14/9
y= 15/29
