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JulijaS [17]
3 years ago
8

Which fraction below represents a terminating decimal? A. B. C. D.

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

3/10

Step-by-step explanation:

The fraction, 1/12, can be written as 1/4 * 1/3. Since we know that 1/3 = 0.333333... and it doesn't terminate, we know that 1/12 doesn't terminate. Similarly 2/9 = 2/3*1/3 and 2/3 = 2*1/3, and neither of these fractions terminate. But, when dividing 3/10, you get 0.3, which terminates.

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The smallest natural number divisible by 2 is 2. 2 divided by 2 is 1. Or 4 divided by 2 is 2 which divided by 2 is 1.
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What value of a make the equation 14-a=19-12
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14-a=19-12\\14-a=7\\a=14-7\\a=7

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Find the greatest common factor of 15x^2y^3 and -18x^3yz <br> The Answer has to be like _x_y_
Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0
4 years ago
Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)
timofeeve [1]

Answer:x-2y-2=0

Step-by-step explanation:

Given :

f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8

Point of intersection :

f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}

x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75

So, we have points \left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )

Equation of line passing through two points \left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right ) is given by y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )

Let \left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )

So, equation is as follows :

y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0

4 0
4 years ago
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