Since you were able to type that negative, I will assume that
f(x)=-x^2+3x+8
the vertex is where the graph changes from increasing to decreasing or vice verca
find theh vertex
-b/2a is x coordinate of vertex where
f(x)=ax^2+bx+c
a=-1
b=3
-3/2(-1)=-3/-2=3/2
we see that the leading coeficient (a) is negative so the graph opens down
it increases then decreases at the vertex
so from negative infinity to 3/2 is interval
in interval nottaion
(⁻∞,3/2]
Answer:
y+1=(x+7)/3
Step-by-step explanation:
slope = (-1-3)/(-7-5) = -4/-12 = 1/3
b = 3-(1/3)×5 = 4/3
y = mx+b
or, y = x/3+4/3
its point slope form,
y = x/3+4/3
or, y=(x+4)/3
or, y+1=(x+4)/3+1
or, y+1=(x+4+3)/7
or, y+1 =(x+7)/3
2. 4 2/5
4. 6 3/8
6. 4 5/12
8. 2 1/3
10. 24 2/3
12. 7 5/6
14. 33/5
16. 102/11
18. 81/5
20. 163/7
22. 1295/6
24. 1329/16
Answer: 1:2
Step-by-step explanation: plz mark me brainliest
Step-by-step explanation:
the formula of coordinates (x, y) that reflected across the x-axis : (x, y) => (x, -y)
so,
A(3, -2) => A'(3, 2)
B(5, 5) => B'(5, -5)
C(-4, 2) => C'(-4, -2)
