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4 years ago

Find three arithmetic means between -2 and 12.

1 answer:

3 0

$a_1=-2;\ a_2;\ a_3;\ a_4;\ a_5=12\\\\a_5-a_1=4d\\\\4d=12-(-2)\\4d=14\ \ \ /:4\\d=3.5\\\\a_2=a_1+d\to a_2=-2+3.5=1.5\\\\a_3=a_2+d\to a_3=1.5+3.5=5\\\\a_4=a_3+d\to a_4=5+3.5=8.5\\\\Solutions:1.5;\ 5\ and\ 8.5$

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If BE−→− bisects ∠ABD and m∠ABD = 66°, find m∠ABE

Monica [59]

Answer:

m∠ABD = 132 °

Step-by-step explanation:

m∠ABE = m∠DBE

and

m∠ABD = m∠ABE + m∠DBE

Because m∠ABE = 66°, therefore m∠DBE = 66°, so that

m∠ABD = 66° + 66° = 132°

4 0

4 years ago

What is the probability of rolling a dice at most 3 times until a 6 occurs

IRISSAK [1]

Answer:

Probablity of getting six in at most three roll= 0.199.

Step-by-step explanation:

Given: Dice rolled at most 3 times untill a 6 occurs.

First, finding the probablity of getting 6 in a dice if rolled once.

Probablity= $\frac{chances\ of\ occurance}{Total\ number\ of\ event}$

We know, dice have six side, therefore, total number of event will be 6.

∴ Probablity of getting six in one roll= $\frac{1}{6}$

As given, Dice is rolled at most 3 times.

Now, finding the probablity of getting 6 in a dice if rolled 3 times.

∴ Probablity of getting six in three roll= $\frac{1}{6}+(\frac{1}{6})^{2} +(\frac{1}{6})^{3}$

⇒ Probablity of getting six in three roll= $\frac{1}{6}+\frac{1}{36} +\frac{1}{216}$

Taking LCD 216

⇒Probablity of getting six in three roll= $\frac{1\times 36+ 6\times 1+1}{216}$

⇒Probablity of getting six in three roll= $\frac{43}{216}$

∴Probablity of getting six in three roll=0.199

3 0

4 years ago

Find the nonpermissible replacement for a in this expression 7/6a

vredina [299]

The correct answer for the exercise shown above is:

zero (0)

The explanation is shown below:

1. You have the following expression given in the problem above:

7/6a

2. By definition, the nonpermissible replacement for a is the value that make the denominator equal to zero.

3. Keeping this on mind, you have:

7/6a=7/6(0)=7/0

Therefore, as you can see, the answer is: zero (a=0).

6 0

3 years ago

(blank) ÷ by 7 > 800 send help...

Anika [276]

Answer:

(blank) > 5600

Step-by-step explanation:

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4 years ago

In May you used 900 kilowatt-hours of energy for electricity.

Sloan [31]

Answer:

a) "The total electrical energy use was 3,240,000,000 joules."

b) "The average power use is 1210 watts."

Part 1: "To generate the electricity you used, 810 L is needed."

Part 2: "To generate the electricity you used, 214.00 gal is needed."

Step-by-step explanation:

1 kilowatt-hours = $3.6x10^6$ joules

Converting 900 kilowatt-hours to joules, we have:

$900*(3.6*10^6)=3.24*10^9$ joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

The month of May has 31 days and 1 day is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

$\frac{900}{744}=1.21$ kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

"The average power use is 1210 watts."

Part 1:

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

$\frac{9.72*10^9}{12*10^6}=810$

So, 810 liters is needed

"To generate the electricity you used, 810 L is needed."

Part 2:

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you used, 214.00 gal is needed."

7 0

4 years ago