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barxatty [35]
2 years ago
13

Ivanna needs to buy some pencils. Brand A has a pack of 36 pencils for 8.52 . Brand B has a pack of 48 pencils for 9.98 . Find t

he unit price for each brand. Then state which brand is the better buy based on the unit price. Round your answers to the nearest cent.
Mathematics
1 answer:
Taya2010 [7]2 years ago
5 0

Answer:

Brand B is better

Step-by-step explanation:

Brand A's unit price is $0.24

Brand B's unit price is $0.21

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A 275 inch pipe is cut into two pieces. One piece is four times the length of the other. Find the length of the shorter piece.
Darina [25.2K]

Since one piece is four time the length <em>x, </em>we can represent that as 4x.

Thus making the equation:

4x+x=275

5x=275

x=55

4(55)=220

220+55=275

So, the length of the longer piece is 220 inches, and the length of the shorter piece is 55 inches.

3 0
3 years ago
What is the sum of the exterior angles of polygon QRST?
Whitepunk [10]

Answer:

360°

Step-by-step explanation:

The sum of the exterior angles of any polygon is 360°

3 0
3 years ago
Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Write 321x64 in long muliplication
makkiz [27]
Step by step:
3 2 1
× 6 4
————————————-
+ 1 2 8 4
+ 1 9 2 6 0
————————————-
= 2 0 5 4 4
4 0
2 years ago
Identify the maximum or minimum value, domain, and range of the graph of the quadratic function.
Virty [35]

Answer:

See below ~

Step-by-step explanation:

<u>Details of the graph of the quadratic equation</u>

  • Minimum value = <u>-1</u>
  • Domain : <u>all real numbers</u>
  • Range : <u>y ≥ -1</u>
5 0
2 years ago
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