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barxatty [35]
2 years ago
13

Ivanna needs to buy some pencils. Brand A has a pack of 36 pencils for 8.52 . Brand B has a pack of 48 pencils for 9.98 . Find t

he unit price for each brand. Then state which brand is the better buy based on the unit price. Round your answers to the nearest cent.
Mathematics
1 answer:
Taya2010 [7]2 years ago
5 0

Answer:

Brand B is better

Step-by-step explanation:

Brand A's unit price is $0.24

Brand B's unit price is $0.21

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6 times the diffrence of 12 and 9 divided by 3​
tester [92]

Answer:

1

Step-by-step explanation:

The difference of 12 and 9 is 12 - 9 = 3

Then 3 ÷ 3 = 1

5 0
2 years ago
1. What is the radius<br> (1 Point)<br> 11 cm
mr_godi [17]

Given that we need to determine the radius of the circle.

<u>Radius:</u>

By definition of radius of circle, the radius is the  length of the line which is drawn from the center of the circle to any point on the circle.

From the figure, we need to determine the radius of the circle.

As, we can see that, the distance from the center of the circle to the point on the circle is 11 cm.

Since, we know that, the radius is the distance from the center of the circle to the point on the circle then, the radius of the given circle is 11 cm

Thus, radius of the circle is 11 cm.

3 0
3 years ago
If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

so that

\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34

So we end up with

\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}

###

Another way to do this:

\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}

\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
3 years ago
A car sells for 16,000. If the rate of depreciation is 18%, find the value of the car after 8 years.
Black_prince [1.1K]

Answer:

Step-by-step explanation:

price after 8 years Amount=P(1-0.18)^8

Amount=16,000(1-0.18)^8

=16,000(0.82)^8

≈3270.63 $

6 0
3 years ago
Angel got a new phone with Verizon. They charged Angel $50 each month for service, plus an additional $15 per gigabyte of data u
DedPeter [7]

Answer: 15y+50=x

Step-by-step explanation:

5 0
3 years ago
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