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Dmitry [639]
3 years ago
10

Construct a polynomial function with the following properties: fifth degree, 5 is a zero of multiplicity 4, −4 is the only other

zero, leading coefficient is 5
Mathematics
2 answers:
kolezko [41]3 years ago
6 0

Answer:

[tex]p(x)=5(x-5)^4(x+4)[\tex]

Step-by-step explanation:

If an nth order  polynomial P(x) has a zero, say w, then P(x) can be written as P(x)=(x-w)Q(x) for some Q(x) , a polynomial of degree (n-1). So, 5 is a zero with multiplicity 4, then {tex]P(x)=(x-5)^4 Q(x) [\tex} for some Q(x). -4 is the only other zero, so (x-(-4))=(x+4) is a factor of Q(x). P(x) is of fifth degree , so we have exhausted the possibilities to [tex]p(x)=(x-5)^4(x+4)R(x)[\tex] where R(x) is of degree 0 or a constant. But the leading coefficient is 5, so is the answer.

mario62 [17]3 years ago
5 0
5(x-5)^4(x+4)
you raise x-5 to the 4th power because 5 has a multiplicity of 4
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Step-by-step explanation:

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3 years ago
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3 years ago
Please help ASAP! I will mark BRAINLIEST! Please answer CORRECTLY! No guessing! CHECK ALL THAT APPLY
skad [1K]

Answer:

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Step-by-step explanation:

The inequality 3x ≥ 96, means that x and 3 must be multiplied to get a product that is <u><em>greater</em></u> than 96.  So to figure this out, you must plug in the numbers given for x, like so:

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A tip that makes this easier is that, you can see that 31 multiplied by 3 is 93, which is only a couple numbers off 96, so all numbers after 31 will result in a product greater than 96. For example:

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nadya68 [22]
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