A half-life of 9 minutes corresponds to a decay factor <em>k</em> such that
Then the time it takes for the substance to decay from 610 g to 124 g is time <em>t </em>such that
Solve for <em>t</em> :
so it takes about 20.7 min for the 610 g sample to decay down to 124 g.
Answer: a) 26
Step-by-step explanation:
-a would be because as you can see there is a pattern of sticks, so what i did was count up the sticks and i found that there was 6 in the first one. So i counted the second one and it was 10 so i realized that all i had to do was add 4.
and for b i think when it says n it means the nth term which is 4 so i think it means pattern 4 which would be 18 so try that out
hope this helped x
Answer:
#1. Identity #2. 0 #3. No solution
Step-by-step explanation:
#1.
5y + 2 = (1/2)(10y+4)
5y + 2 = 5y + 2
This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).
#2.
0.5b + 4 = 2(b+2)
0.5b + 4 = 2b + 4
0.5 b - 2b = 0
b = 0
#3.
-3x + 5 = -3x + 10
This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.
Answer:
No solutions
Step-by-step explanation:
In this question, you would be solving for x.
Solve:
5 + 2(3 + 2x) = x + 3(x + 1)
Use the distributive property.
5 + 6 + 4x = x + 3x + 3
Combine like terms.
11 + 4x = 4x + 3
Subtract 4x from both sides.
11 = 3
Since we don't have an "x value", there are no solutions.
"No solutions" would be your answer.
The answer is $12,052.5. youd divide 800 into 1500 then you multiply the answer you get by 6400 then add (1500/100) x 3.5 to get your answer.
