The second question is the first choice
Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
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<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
Since the given problem states that the two angles, angle
1 and angle 2 form a linear pair, this means that they form a 180° line, so
that:
measure angle 1 + measure angle 2 = 180°
Since measure of angle 2 is six more than twice the
measure of angle 1, therefore:
measure angle 2 = 2 (measure angle 1) + 6
hence, substituting this into the first equation:
measure angle 1 + 2 (measure angle 1) + 6 = 180
3 (measure angle 1) = 174
measure angle 1 = 58°
Therefore,
measure angle 2 = 2 (measure angle 1) + 6
measure angle 2 = 2 (58°) + 6
<span>measure angle 2 = 122°</span>
Answer:
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Step-by-step explanation:
