Let x be the jug, for half-filled, y for the weight of the jug when empty.
∵ x + y = 2.6 kg
∵ x = 4 kg
∴ ⋅ 4 + y = 2.6 kg
∴ 2 + y =2.6 kg
∵ y = 2.6 - 2 = 0.6 kg
∴ The weight of the empty jug = 0.6 kg
What is the center and radius of the circle given by x2 + y2 - 10x - 12y + 24 = 0?
1 answer:
Answer:
centre (5, 6 ) , r =
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r the radius
given
x² + y² - 10x - 12y + 24 = 0 ( collect x and y terms together and subtract 24 from both sides )
x² - 10x + y² - 12y = - 24
using the method of completing the square
add ( half the coefficient of the x / y terms)² to both sides
x² + 2(- 5)x + 25 + y² + 2(- 6)y + 36 = - 24 + 25 + 36
(x - 5)² + (y - 6)² = 37 ← in standard form
with centre (h, k ) = (5, 6 ) and r =
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