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xenn [34]
2 years ago
6

PLEASE HURRY

Mathematics
1 answer:
Irina18 [472]2 years ago
3 0
It would be A or C
I’m not sure if you’re supposed to use brackets or parentheses
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A worded math problem that = 5
vazorg [7]

Answer:

Seven take away two is equals to five

Step-by-step explanation:

<u>Because</u>,

Seven take away two is equals to five

<u>is </u><u>the </u><u>same </u><u>to</u>

7 - 2 = 5

7 0
3 years ago
 
slava [35]

Answer:The area of the base will be (1)(3) m

The area of the right and left lateral faces will be (1)(2) = 2m

The area of the front and back lateral faces will be (2)(3) = 6m

The lateral area of the prism will be 16 m

Step-by-step explanation:

5 0
3 years ago
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If a number has an infinite amount of 0's on the end of it, can I shorten it to just one 0?
Alex777 [14]

yea just put a line over the 0 to indicate it's infinite

7 0
3 years ago
2x^3-x^2+x-2 factorize​
bekas [8.4K]

Answer:

(x-1)(2x^2+x+2)

Step-by-step explanation:

Factorize:

f(x)=2x^3-x^2+x-2

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

4 0
3 years ago
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Please help❤️❤️ It’s for 20 pts!!
solong [7]
If you need part A, draw a person and label them 6 feet tall and a shadow coming off of him that is five feet long and draw a basketball hoop that and label it X feet tall and draw a shadow coming from it that is 8 feet long. To solve, you use proportions 6/5=X/8 solving this you get X=9.6 feet which is the height of the rim. Therefore, the rim does not meet regulation height, since the required height (10 feet) is greater than the actual height (9.6 feet).   
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