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2 years ago

Please find 2/3 minus 3/5

1 answer:

6 0

First we need common denominators so we could multiply 2/3 by 5 and 3/5 by 3. Now we have 10/15 and 9/15. 10/15 - 9/15 = 1/15. The answer would be 1/15. Hope this helps and please mark brainliest!

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How many men have a waist measurement of more than 85cm

Llana [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1/4+4=3/4(t+8) show work!!<br> will mark as brainlest!

-BARSIC- [3]

Answer:

t=-7/3

Step-by-step explanation:

1. Distribute 3/4 through the parenthesis.

3/4(t + 8) Multiply 3/4 by the numbers in the parenthesis.

So now we have 1/4 + 4= 3/4t + 6

2.Combine like terms.

The sum of 1/4 and 4 can equal 17/4.

So now we have 17/4=3/4t+6

3. Multiply both sides of the equation by the denominator of 4.

It will look like 4 x 17/4 = 4(3/4t + 6)

4. Distribute 4 through the parenthesis.

4 x 17/4=4 x 3/4t + 4 x 6

5. Reduce the numbers with the greatest common divisor 4. Then Multiply the numbers.

Now we have 17=3t+24

6. Subtract 24 from 17. That equals -7.

So now we have -7=3t

Dive -7 by 3t.

Your answer is now -7/3.

6 0

3 years ago

7th grade math help me please :)

Yuliya22 [10]

Answer:

$288

Step-by-step explanation:

16+8=24

$24 per book

24 x 12 = 288

7 0

3 years ago

First accurate commenter gets brainliest

BlackZzzverrR [31]

Answer:

Graph #4 is the correct answer.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If z varies directly with x and inversely with the cube of y, when x=8,y=2 and z=3, what is x when y=4 and z=9/32?

Degger [83]

$\bf \qquad \qquad \textit{double proportional variation}
\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{\underline{z} varies directly with \underline{x} and inversely with the cube of \underline{y}}\qquad z=\cfrac{kx}{y^3}$

$\bf \textit{we also know that }
\begin{cases}
x=8\\
y=2\\
z=3
\end{cases}\implies 3=\cfrac{k8}{2^3}\implies 3=\cfrac{8k}{8}\implies 3=k
\\\\\\
therefore\qquad \boxed{z=\cfrac{3x}{y^3}}
\\\\\\
\textit{when y = 4 and }z=\frac{9}{32}\textit{ what is \underline{x}?}\qquad \cfrac{9}{32}=\cfrac{3x}{4^3}\implies \cfrac{9}{32}=\cfrac{3x}{64}
\\\\\\
\cfrac{9\cdot 64}{32\cdot 3}=x$

5 0

4 years ago