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2 years ago

FIRST TO ANSWER GETS BRAINLIEST

Mathematics

1 answer:

disa [49]2 years ago

8 0

Answer:

about <u>1575</u> sqaure meters

Step-by-step explanation:

1. Create An equation

Formula Area of trapeziod: 1/2x(b1+b2)xh

1/2x(40+50)x35=Area

1/2x90x35=Area

45x35=Area

Area=1575 because the shape is a trapeziod according to the information in the problem which we can just then use the formula to calculate the area.

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Can someone please solve this problem for me?

statuscvo [17]

Answer:

5 and 7.

Step-by-step explanation:

Hey! So to start you need to create an algebraic expression. You can express this problem through the following equation:

*Note: if x is an odd integer, x + 2 is the next consecutive odd integer.

$x *(x+2)=35$

Expanding, you get:

$x^{2}+2x = 35.$

And moving the 35 to the other side, you get a simple quadratic.

$x^{2}+2x -35 =0.$

Solving by factoring:

$(x+7)(x-5)$

This means two possible solutions for the smaller consecutive number are -7 and 5. However the question asks for two positive odd integers, so one of the numbers must be 5. The next will be 7(as its x + 2).

5 0

3 years ago

Parallel lines x and w are cut by transversals z and y and form 4 angles at each intersection. Where line x intersects with line

Sunny_sXe [5.5K]

Answer:

m∠1°= 75°

m∠2°= 105°

Step-by-step explanation:

It's on edg.

5 0

3 years ago

Read 2 more answers

A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

3 years ago

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

$t = 3.054$

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

3 years ago

9 squared ? 11 ? 8 ? 4 ? 1 = 60 The ? Can be +,-,x or d division

dexar [7]

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5 0

3 years ago