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velikii [3]
2 years ago
15

If angle three is equal to 6x+16 and angle seven is equal to 2x+2 , solve for x.

Mathematics
2 answers:
neonofarm [45]2 years ago
8 0

Step-by-step explanation:

3 and 7 are equal because they are corresponding angles

6x+16=2x+2

6x-2x=2-16

4x= -14

x= -3.5

SashulF [63]2 years ago
5 0

Answer:

-3.5

Step-by-step explanation:

6x + 16 = 2x + 2

4x = -14

x = -3.5

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2. An electronics store sold 1,500 CD's this year. The previous year, the store sold 990
Vera_Pavlovna [14]

Answer:

52%

Step-by-step explanation:

First, find the difference between this year's sales and the previous'. 1500-990=510.

Now we can divide 990 by 510 to find the percent increase. 510/990=0.515151515152, or 52%.

8 0
2 years ago
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The ratio of two complementary angles is 5:4. Find the measure of both angles.
grandymaker [24]

Answer:

50 degrees and 40 degrees

Step-by-step explanation:

50 degrees and 40 degrees

complimentary = add up to 90 degrees

5:4:9

50:40:90

7 0
3 years ago
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Latrell bought 4 bags of powdered sugar. He got a total of 5 1/2 cups of sugar. How many cups of sugar were in each bag?
Stels [109]
So all 4 bags of sugar yielded 5 and 1/2 cups..... well.. how many in each one?  well, let's split the 5 and 1/2 evenly in 4 pieces.

\bf \stackrel{mixed}{5}\frac{1}{2}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}}\\\\
-------------------------------\\\\
\cfrac{\quad\frac{11}{2} \quad }{4}\implies \cfrac{\quad\frac{11}{2} \quad }{\frac{4}{1}}\implies \cfrac{11}{2}\cdot \cfrac{1}{4}\implies \cfrac{11}{8}\implies \stackrel{cups}{1\frac{3}{8}
}
5 0
2 years ago
What is the surface area of this right rectangular prism?
vagabundo [1.1K]

Answer:

A≈32\frac{3}{10}ft²

--

To find the surface area of a right rectangular prism you must use this formula A=2(wl+hl+hw)

Then plug in your variebles

A=2( 1.33*1.5+5+1.5+5+1.33)

This comes out to be A≈32 \frac{3}{10}

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
2 years ago
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