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Anastasy [175]
2 years ago
15

What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma

l table given to help answer the question. A normal curve with a peak at 0 is shown. The area under the curve shaded is 1 to 2. Z Probability 0. 00 0. 5000 1. 00 0. 8413 2. 00 0. 9772 3. 00 0. 9987 0. 14 0. 16 0. 86 0. 98.
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

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Round each number to the nearest hundredth.
viva [34]
243.87 and 132.37 thts the answer
4 0
4 years ago
The midpoint of segment AB is (-7, 10) and endpoint A is located at (3, -1). Find the other endpoint B. Show all work.
dusya [7]

Answer:

B(-17,21)

Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

A(3, -1)

and we let the other end point B be B(x,y)

and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

\frac{3+x}{2}=-7\\3+x=2*-7\\3+x=-14\\x=-14-3\\x=-17

and now solving for y:

\frac{-1+y}{2}=10\\-1+y=2*10\\-1+y=20\\y=20+1\\y=21

So, the other point B is:

B(-17,21)

6 0
3 years ago
I need help please and fast
patriot [66]

Answer:

20%

Step-by-step explanation:

The reason it is 20% is due to the fact that if you put it in a form showing 250/250 = 100/100 and put another proportional rate underneath it showing 200/250 = x/100, you would have to multiply the numerator of the fraction on the left by the denominator of the fraction on the right to get 20000. Now you divide 250 from 20000 and get x for 80, resulting in 80/100 or 80%. All you have to do now is subtract 100-80, which equals 20, resulting in 20%.

Hope that helps!! It's my first time in answering so, ya. ;D goodluck!

3 0
3 years ago
Read 2 more answers
Please help.<br> A<br> B<br> C<br> D
s344n2d4d5 [400]

Answer:

A. t(x) = 450 - 0.06x

Step-by-step explanation:

The layer which is originally 450 m thick is decreasing by 0.06 m.

450 - 0.06

... per day. x represents days.

0.06x

So,

450 - 0.06x

6 0
3 years ago
A bag contains 6 red marbles, 10 white marbles, and 7 blue marbles. You draw 4 marbles out at random, without replacement. What
Lapatulllka [165]

Answer:

3/1771

Step-by-step explanation:

Probability is the chance or likelihood that an event will occur.

Probability = expected outcome/total outcome

Total outcome = total number of marbles

Total outcome = 6+7+10 = 23marbles

If four marbles are drawn, the probability that they are all red is expressed as;

Pr(picking the first red marble) = 6/23

Since it is without replacement, the total marble becomes 22

Pr(picking the second) = 5/22

Pr(picking the third marbles = 4/21

Pr(picking the 4th marble) = 3/20

Note that the number of red marbles keep reducing and the total marble keep reducing as well.

Pr(picking the 4marbles) = 6/23×5/22×4/21×3/20 (we multiplied because or is an independent events)

Pr(picking the 4marbles) = 360/212520

Pr(picking 4 red marbles) = 72/42504 =36/21,252

= 9/5313

= 3/1771

Hence the probability of picking 4 marbles at random without replacement is 3/1771

4 0
3 years ago
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