I believe it would be multiplied by -0.5 or -1/2.
Answer:
Below.
Step-by-step explanation:
I'll write sin x as s and cos x as c so we have:
(1 + s +c)/(1 + s - c) = (1 + c)/s
Cross multiplying:
s + s^2 + cs = 1 + s - c + c + cs - c^2
s + s^2 + cs = 1 + s + cs - c^2
s^2 + c^2 + s - s + cs - cs = 1
s^2 + c^2 = 1.
- that is sin^2 x + cos^2 x = 1 which is a known identity.
Therefore the original identity is proved.
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
Answer:
terms- + -
variables- x p
coefficent-7 3
constant- 9
Step-by-step explanation:
Step-by-step explanation:
- 2x-2y=-6
3x+4y=8
multiply equation (1) by 3 and equation (2) by 2
- 6x-6y=18
6x+8y=16
Add
2y=34
y= 34÷2
y=17
substitute 17 for y in equation (2)
3x+4y=8
3x+4(17)=8
3x+68=8
3x=8-68
3x=-60
x=-60÷3
x=-20
x=-20,y=17
