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Aleks [24]
2 years ago
14

(2.3×10^4)×(1.5×10^-2)

Mathematics
2 answers:
Wewaii [24]2 years ago
6 0

Answer:

3450

Step-by-step explanation:

(2.3x10^4)x(1.5x10^-2)

(2.3x10,000)x(1.5x.1)

23,000x.15

3450

Tcecarenko [31]2 years ago
6 0
The answer is 3450 but next time use photomath bc its easier
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The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi
Dmitrij [34]

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable. The values given in the table 3 matches the equation and includes the viable solutions.

<h3>Given information-</h3>

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation,

c=3.5b

The quantity of the bread depends on the quantity of the loaves.

<h3>Dependent variable</h3>

The dependent variable is the variable that depends on the value of other variable and keeps on changes with change in the value of one variable.

Lets check which table satisfy the above equation.

Table 1-

In the table the first values of the bread and the loves is -2 and -7. The quantity of a bread and loves can not be negative. Thus the table 1 does not provides the viable solution.

Table 2-

In the table 2 the value of the third row is 1.5 loaves and 5.25 breads. Check this by the given equation. When the value of loaves is 1.5 then the value of the bread is,

c=3.5\times1.5

c=4.5

The value of bread must be 4.5. Thus the table 2 does not provides the viable solutions.

Table 3-

Put the values of the loaves in the given equation one by one,

When the value of loaves is 0 then the value of the bread is,

c=3.5\times0=0

When the value of loaves is 3 then the value of the bread is,

c=3.5\times3=10.5

When the value of loaves is 6 then the value of the bread is,

c=3.5\times=21

When the value of loaves is 9 then the value of the bread is,

c=3.5\times9=31.5

All the values of the table 3 satisfies the given equation.

Hence, the values given in the table 3 matches the equation and includes the viable solutions.

Learn more about the dependent variables here;

brainly.com/question/967776

8 0
2 years ago
F() = 37. What are the domain and range of f-12)?
Gwar [14]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Your team wins 18 medals at a competition. The metals are gold, silver, and bronze in a ratio of 2:4:3. How many of each metal d
Anarel [89]

Answer

Find out the how many of each metal did your team win.

To prove

As given

Your team wins 18 medals at a competition.

The metals are gold, silver, and bronze in a ratio of 2:4:3.

Let us assume that x be the scalar multiple of the gold, silver and bronze medal.

Thus

Number of gold medal = 2x

Number of silver medal = 4x

Number of bronze medal = 3x

Than the equation becomes

2x + 4x + 3x = 18

9x = 18

x = \frac{18}{9}

x = 2

Number of gold medal = 2 × 2

                                      = 4

Number of silver medal = 4 × 2

                                       = 8

Number of bronze medal = 3 × 2

                                           = 6

Therefore the number of gold medal are 4, silver medal are 8, bronze medal are 6.

3 0
3 years ago
Please help I will mark you as brainliest
Vilka [71]

Answer:

3999

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use long division to divide x^3+x^2-2x+14 by x+3
bekas [8.4K]

First, x^3=x^2\cdot x, and if we multiply x+3 by x^2 we get

x^3+3x^2

Subtracting this from the numerator gives a remainder of

-2x^2-2x+14

Next, -2x^2=-2x\cdot x, and if we multiply x+3 by -2x we have

-2x^2-6x

and subtracting this from the previous remainder, we end up with a new remainder of

4x+14

Next, 4x=4\cdot x, and if we multiply x+3 by 4 we get

4x+12

Subtracting from the previous remainder, we get a new remainder of

2

which contains no more factors of x, so we're done.

So,

\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}

8 0
3 years ago
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