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OlgaM077 [116]
3 years ago
8

Explain the relationship between the polynomial identities: x^2 − 1 = (x +1)(x − 1) and x^2 − a^2 =(x − a)(x +a).

Mathematics
1 answer:
Bess [88]3 years ago
5 0

Answer:

So these two equation can be related by identity x^2-a^2=(x+a)(x-a)

Step-by-step explanation:

We have given equation x^2-1=(x+1)(x-1)

And x^2-a^2=(x+a)(x-a)

We know the algebraic identity a^2-b^2=(a+b)(a-b)

From this identity

x^2-1 can be written as (x+1) (x-1)

And using same identity x^2-a^2 can be written as (x-a)(x-b)

So these two equation can be related by identity x^2-a^2=(x+a)(x-a)

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A person invest $10,000 into a bank the bank pays 4.75% interest compounded semi annually. To the nearest 10th of a year, how lo
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Answer:

T is 13.9 years to the nearest 10th of a year

Step-by-step explanation:

In this question, we are to calculate the number of years at which someone who invests a particular amount will have a particular amount based on compound interest.

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Mathematically,

A = P(1+ r/n) ^nt

Where A is the final amount after compounding all interests which is $19,200 according to the question

P is the initial amount invested which is $10,000 according to the question

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n is the number of times per year in which interest is compounded. This is 2 as interest is compounded semi-annually

t= ?

we plug these values;

19200 = 10,000(1+0.0475/2)^2t

divide through by 10,000

1.92 = (1+0.02375)^2t

1.92 = (1.02375)^2t

We find the log of both sides

log 1.92 = log [(1.02375)^2t)

log 1.92 = 2tlog 1.02375

2t = log 1.92/log 1.02375

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t = 27.79/2

t = 13.89 years

The question asks to give answer to the nearest tenth of a year and thus t = 13.9 years

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