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disa [49]
2 years ago
11

Find the length of BC.Explain how you got it, please!Thanks!

Mathematics
2 answers:
egoroff_w [7]2 years ago
8 0

Answer:

BC = 30.7 units (nearest tenth)

Step-by-step explanation:

As ∠AQR = ∠CQR  then ∠AQB = ∠CQD

This means that ΔABQ ~ ΔCDQ

Therefore, the side lengths of two similar triangles are proportional.

\begin{aligned} \sf \dfrac{AB}{CD} & =\sf \dfrac{BQ}{QD}\\\sf \implies \dfrac{32}{19.2} & =\sf \dfrac{15.0}{QD}\\\sf \implies QD & = \sf 9 \end{aligned}

Pythagoras' Theorem:  \sf a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given:

  • a = BD = BQ + QD = 15 + 9 = 24
  • b = CD = 19.2
  • c = BC

Substituting values into the formula:

\begin{aligned}\sf 24^2+19.2^2 & = \sf BC^2\\\sf BC^2 & = \sf 944.64\\\sf BC & = \sf \pm\sqrt{944.64}\\\sf BC & = \sf 30.7 \ (nearest \ tenth)\end{aligned}

(since distance is positive only)

Vinvika [58]2 years ago
4 0

Answer:

BC = 30.73

Here,

\sf \frac{AB}{BQ}  = \frac{CD}{DQ}

so first solve for QD

\sf \hookrightarrow \frac{32}{15}  = \frac{19.2}{DQ}

\sf \hookrightarrow 32(DQ)}  =19.2(15)

\sf \hookrightarrow 32(DQ)}  =288

\sf \hookrightarrow DQ =9

  • Hence, QD = 9

Now! <u>using Pythagoras theorem,</u>

  • CD² + BD² = BC²
  • 19.2² + (9+15)² = BC²
  • BC = √368.64+576
  • BC = 30.73499634
  • BC = 30.73 ( rounded to nearest hundredth )
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