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jenyasd209 [6]
3 years ago
9

Solve |2x- 6|<10 O XI-2 O [xl-8 O x12

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

[xl-8

Step-by-step explanation:

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Helpp please thanksss
Brilliant_brown [7]

Answer:

The function show the value of the machinery after "t" years.

So After "4" years... Input "t" as 4 to get its value

f(t) = 12,500 - 1,600(4)

=$6,100

OPTION C IS LEGIT!!!

8 0
3 years ago
Can someone check if this is right and correct me if it’s not????
mylen [45]

Answer:

No. it is not tangent to the circle ⇒ A

Step-by-step explanation:

In any circle a tangent and a diameter are perpendicular at one end of the diameter

In the attached figure

∵ The line segment drawn from point A is passing through

   the center of the circle

∴ This line segment is a diameter of the circle

∵ If AB is a tangent to the circle at point A

- That means the diameter and the tangent meet each other

  at point A (one end of the diameter)

∴ AB and the diameter are perpendicular at point A

∴ m∠A = 90°

Now let us check if the lengths of the triangle formed a right angle triangle or not by using the inverse of Pythagoras Theorem

<em>In a triangle if the square of the longest side is equal to the sum of the squares of the other two sides, then the triangle is a right triangle at the vertex which opposite to the longest side</em>

∵ 17 is the longest side in the triangle

∵ The other two sides are 10.2 units and 6.8 units

∵ (17)² = 289

∵ (10.2)² + (6.8)² = 150.28

∴ (17)² ≠ (10.2)² + (6.8)²

∴ The triangle can not be a right triangle because the square

    of the longest side is not equal to the sum of the squares of the

    other two sides

∵ ∠A is opposite to the longest side

∴ m∠A ≠ 90°

∴ Line AB is not perpendicular to the diameter at A

∴ Line AB is not a tangent to the circle

5 0
3 years ago
Can someone answer this??
Yuri [45]

Answer:

B. -0.4 ÷ 0.25

I hope it helps..

8 0
3 years ago
How to find the median of <br><br> E)6,10,12,5,7,12,9
emmasim [6.3K]
First you order them from least to greatest.

5, 6, 7, 9, 10, 12, 12

Then you cross off one number from each side until you get to the middle

Medial = 9
6 0
4 years ago
Read 2 more answers
Which expression is equivalent to (x+2)(3x-3)
navik [9.2K]

Answer:

3x^2+3x-6

Step-by-step explanation:

\left(x+2\right)\left(3x-3\right)

Use FOIL.

x\cdot \:3x+x\left(-3\right)+2\cdot \:3x+2\left(-3\right)

3xx-3x+2\cdot \:3x-2\cdot \:3

3x^2-3x+2\cdot \:3x-2\cdot \:3

3x^2-3x+6x-6

3x^2+3x-6

7 0
3 years ago
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