Reflect the shape A in the line x=1
1 answer:
Answer:
reflected image shown in red on attached diagram
Step-by-step explanation:
When reflecting an object in the line x = a:
- reflected x-values: 2a - x
- reflected y-values are the same as the original y-values
So when reflecting in the line x = 1
- given x-value = 2, so reflected x-value = 2(1) - 2 = 0
- given x-value = 4, so reflected x-value = 2(1) - 4 = -2
(2, 7) → (0, 7)
(2, 4) → (0, 4)
(4, 4) → (-2, 4)
You might be interested in
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2