which of the following species of fish would likely contain the highest levels of contaminants? mahi-mahi swordfish flounder sal
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Answer:
The age difference between the oldest and the youngest is 48.
Explanation:
Given the following data;
The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.
The ratio of the ages of Esinam (E) and Larry (L) is 3:5.
The sum of the ages of all three is 147.
Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);
LCM of 3,5 = 15.
Hence, the ratio of the three ages is now;
K:E:L = 9:15:25
Let their ages be denoted by x;
The sum of all three ages is;
9x + 15x + 25x = 147
49x = 147
x = 147/49
x = 3.
To find the age difference between the oldest and the youngest;
The oldest is Esinam = 25x
The youngest is Kisii = 9x
Therefore, 25x - 9x = 16x
Substituting the value of x, we have;
x = 3; 16x = 16(3) = 48.
The age difference between the oldest and the youngest is 48.