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Triss [41]
3 years ago
10

True or False: As the environment becomes less polluted, the number of light colored moths is able to decrease.

Biology
1 answer:
kotykmax [81]3 years ago
5 0
This is True because the Eco-System is aways changing since pollution is killing birds animals and other insects.
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Why would the pancreatic enzyme trypsin be non-functional if it was secreted in the stomach instead of the pancreas?
mel-nik [20]

Answer:

-Due to acidic pH of stomach.

Explanation:

Enzymes are generally made up of protein molecules and work at an optimum pH and temperature. This is because at change in pH and temperature leads to denaturation of proteins that cause change in active site of enzyme.

For trypsin, optimum pH is slightly basic as pH (7.5). So, trypsin would become non-functional at acidic pH due to denaturation and loss of active site.

Trypsin is a pancreatic enzyme that works at small intestine as pH of small intestine is slightly basic.Thus, if the trypsin was secreted in stomach instead of pancreas, it would be non-functional as stomach has acidic pH due to stomach acid.

8 0
4 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
Which examples describe how a migratory bird will meet the challenge of reproducing?
skelet666 [1.2K]
<span>The challenge of reproducing is one of important manners which distinguishes migratory birds from another birds. The question is that which examples descrbe such manners, and for that, we can choose A, C and D</span>
6 0
3 years ago
A Chlorella cell viewed through a microscope is 0.00005 m wide when the magnification is 2000.
juin [17]

Answer:

0.0025micrometer.

Explanation:

To calculate the actual size of the image, the formula to be used is

Actual size=Image size÷magnification.

The image size is 0.00005 wide

Magnification is 2000

First, convert the image size to micrometer.

=0.00005 × 1000000

50micrometers.

Actual size= 50÷2000

Actual size = 0.0025

3 0
3 years ago
In what ways are the respiratory structures of all animals similar?
Annette [7]

Answer:

provide a large surface area of moist, selectively permeable membrane.

Explanation:

4 0
3 years ago
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