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1 year ago

5

Nihkil surveyed 20 students at his middle school and 13 of them had at least one sibling. What percent of the students surveyed

have at least one
sibling?

1 answer:

jek_recluse [69]1 year ago

5 0

The answer is 65 percent

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Find the quotient 5/18 divided by 2/6

Gnesinka [82]

5/18 diveded by 2/6 is 5/18*6/2 then its 5/18 * 3 which gives 15/18 or 5/6

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3 years ago

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2 years ago

Lupita rides a taxi that charges a flat rate of $6.75 plus $3.20 per mile. If the taxi charges Lupita $40.03 in total for her tr

Alex777 [14]

Hello! In order to understand this question, we need to take a look at the content that is involved.

Lupita pays $40.03 in total. Meaning that's where we are going to start if we want to find out how many miles her ride was. Since the taxi charges a flat rate of $6.75. We would want to subtract it from her total value because we only work with that flat rate once. Which ends up giving us $33.28. From there, we don't need to worry about the flat rate anymore and we now focus on the mileage. If it costs $3.20 per mile, then we can simply divide the amount after to flat rate by the cost per mile, to figure out how many miles she has gone. In the end, you will get 10.4 miles.

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2 years ago

Based on historical data, your manager believes that 40% of the company's orders come from first-time customers. A random sample

Vedmedyk [2.9K]

Answer:

$P(0.26 \leq p \leq 0.43)=0.7204-0.0032=0.7172$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The population proportion have the following distribution

$p \sim N(p=0.4,\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.4(1-0.4)}{91}}=0.0514)$

And we can solve the problem using the z score on this case given by:

$z=\frac{p_o -p}{\sqrt{\frac{p(1-p)}{n}}}$

We are interested on this probability:

$P(0.26 \leq p \leq 0.43)$

And we can use the z score formula, and we got this:

$P(\frac{0.26 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}} \leq Z \leq \frac{0.43 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}})$

$P(-2.726 \leq Z \leq 0.584)$

And we can find this probability like this:

$P(-2.726 \leq Z \leq 0.584)=P(Z$

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2 years ago