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3 years ago

Need help fast please

Mathematics

2 answers:

lesantik [10]3 years ago

7 0

Answer:

D not here

Step-by-step explanation:

A-2 is not reasonable as it is not possible

C- bot possible

B- maybe

D- most reasonable

anastassius [24]3 years ago

7 0

I think it is C but I’m not 100 percent sure

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deff fn [24]

Answer:

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8 0

3 years ago

Nient and Units

Shtirlitz [24]

The answer is most likely C. Cubic meters.

5 0

3 years ago

-5x-4y=10

strojnjashka [21]

Answer:

y intercept = $(0, ~-\frac{5}{2} )$

x intercept = $(-2, ~0)$

Step-by-step explanation:

$-5x - 5y = 10$

y intercept

$\to x = 0$

$-5(0) - 4y = 10$

$-4y = 10$

$y = \frac{10}{-4}$

$y = -\frac{5}{2}$

so, the answer is $(0, ~-\frac{5}{2} )$

x intercept

$\to y = 0$

$-5x - 4(0) = 10$

$-5x = 10$

$x = \frac{10}{-5}$

$x = -2$

so, the answer is $(-2, ~0)$

Happy to help :)

8 0

3 years ago

Read 2 more answers

A sporting goods store sells triangular team pennants in two sizes. The base of one pennant is 18 in. and the length of the side

juin [17]

This is a proportion problem because the problem stated that the two team pennants are similar.

Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base = 6 in ; length = x ?

9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x

The length of the side of the smaller pennant is 3 inches.

6 0

4 years ago

Read 2 more answers

Raymond just got done jumping at super bounce trampoline center. The total cost of his session was $43.25. He had to pay a $7 en

fgiga [73]

1.25t+7=43.25 can be used to determine the number of minutes that Raymond was on the trampoline.

Step-by-step explanation:

Given,

Total cost for session = $43.25

Entrance fee = $7

Charges per minute = $1.25

Let,

t be the number of minutes raymond was on Trampoline

Total cost for session = entrance fee + Charges per minute * No. of minutes

$43.25=7+1.25*t\\1.25t+7=43.25$

1.25t+7=43.25 can be used to determine the number of minutes that Raymond was on the trampoline.

Keywords: linear equation, addition

Learn more about linear equations at:

#LearnwithBrainly

4 0

3 years ago