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3 years ago

Need help fast please

Mathematics

2 answers:

lesantik [10]3 years ago

7 0

Answer:

D not here

Step-by-step explanation:

A-2 is not reasonable as it is not possible

C- bot possible

B- maybe

D- most reasonable

anastassius [24]3 years ago

7 0

I think it is C but I’m not 100 percent sure

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If f(x) varies directly with x2, and f(x) = 40 when x = 2, find the value of f(5).

Paraphin [41]

Answer:

C.250

Step-by-step explanation:

If f(x) varies directly with x^2

f(x) = k * x^2

f(x) = 40 when x=2. Substitute these values in

40 = k(2)^2

40 = k*4

Divide by 4

40/4 = 4k/4

10 =k

f(x) = 10x^2

Now we want to find f(x) when x=5. Substituting

f(5) = 10 *5^2

f(5) = 10 *25

f(5) = 250

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3 years ago

How do you solve this? Show work and answer

zalisa [80]

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8 0

3 years ago

Read 2 more answers

What is the x-component of the electric field at (x, y) = (0 m, 4 m)??

Elza [17]

(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.

8 0

3 years ago

Information about the proportion of a sample that agrees with a certain statement is given below. Use StatKey or other technolog

lara31 [8.8K]

Answer:

$SE=\sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.35 (1-0.35)}{100}}=0.048$

If we replace the values obtained we got:

$0.35 - 1.96\sqrt{\frac{0.35(1-0.35)}{100}}=0.257$

$0.42 + 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.443$

The 95% confidence interval would be given by (0.257;0.443)

Step-by-step explanation:

Notation and definitions

$X=35$ number of people that agree.

$n=100$ random sample taken

$\hat p=\frac{35}{100}=0.35$ estimated proportion of people that agree

$p$ true population proportion of peopl that agree

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: