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Nat2105 [25]
4 years ago
9

Blake watched of a movie on Friday, of the movie

Mathematics
1 answer:
xeze [42]4 years ago
7 0

Answer:

1/3

Step-by-step explanation:Because he split the movie into 3 parts

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A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L
Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider \Delta ABC as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}

From the given data, L=15\:ft=AC, y=9\:ft=AB and x=BC

Substituting the values,  

\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}

\therefore 81+x^{2}=225

\therefore x^{2}=225-81

\therefore x^{2}=144

\therefore \sqrt{x^{2}}=\sqrt{144}

\therefore x=\pm 12

Since length can never be negative, so x= 12.

Now to calculate \dfrac{dy}{dt} again consider following equation,  

\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}

Differentiate both sides of the equation with respect to t,  

\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)

Applying sum rule of derivative,

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)

Applying power rule of derivative,  

2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0

Simplifying,  

y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0

Substituting the values,  

9\dfrac{dy}{dt}+12\times1.5=0

9\dfrac{dy}{dt}+18=0

Subtracting both sides by 18,

9\dfrac{dy}{dt}=-18

Dividing both sides by 9,

\dfrac{dy}{dt}= - 2

Here, negative indicates that the ladder is sliding in downward direction.  

\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}

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3 years ago
Anne wants to tie a support line from the top of a 50 foot radio tower to an anchor spot 30 feet from the tower’s base. Approxim
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Use the pythagorean theorem to find the answer. 
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In rectangle QRST, diagonals QS and RT are drawn and intersect at point P. Which of the following st
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La'Vonn rolled a die 100 times. His results are below. What is the relative frequency for La'Vonn rolling a 3?
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