The national interest rate on houses for 25 years is 4.3%. The banker wishes to test that the local interest rates are lower than the national rate. So he should use the initial data of 4.3% interest as his base data. Then he should investigate the rates of houses in the local vicinities and compare it to his base data.
Answer:
24cb 18 hb
Step-by-step explanation:
Let's call C the number of cheese burger sold and H the number of hamburgers.
As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:
C= (3/4)H (equation 1)
The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:
C + H = 42
Replacing C by its value of eq. 1:
(3/4)H + H = 42
(3/4)H + (4/4)H = 42
(7/4) H = 42
Dividing both sides by (7/4)
H = 42/(7/4)
H= 42*(4/7)
H= (42/7)*4
H= 6*4
H=24
Then, C is:
C=(3/4)H
C=(3/4)*24
C= 3*24/4
C=72/4
C=18
We can verify it summing C+H
C+H=24+18=42 verified!
We have that
cos A=0.25
so
A=arc cos (0.25)-------> using a calculator----> A=75.5225°
Round to the nearest hundredth-----> A=75.52²
the answer is
the option <span>75.52°</span>
Answer: 5 sour straws
Step-by-step explanation: If he spends 7.50, then he still has 7.50 left. 7.50 / 5= 1.50
Continuous compounding is the mathematical limit that compound interest can reach.
It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A every infinitesimally small instant.
The limit of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).
Say we invest $1000 at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-
1000 ( 1 + 0.02/365)^365 = $1020.20
with continuous compounding this will be
1000 * e^1 = $2718.28
