In addition to what Paul in CT said, 13 is a member of the natural numbers, whole numbers, rational numbers, real numbers, complex numbers, and algebraic numbers.
A is a subset of B is all the elements of A are elements of B
Answer:
For
x
=
6
y
=
−
6
+
6
y
=
0
or
(
6
,
0
)
Second Point: For
y
=
4
y
=
−
4
+
6
y
=
2
or
(
4
,
2
)
We can next plot the two points on the coordinate plane:
graph{((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y+x-6)((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}
Step-by-step explanation:
This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
The correct answer is C.
Because by looking at the diagram you can see that angles 7 and 8 are intersected
Answer:
Hello there!
Since he had 6 candies and lost two, all you have to do is subtract 2 from 6.
Therefore, Jerry only has 4 candies.
Hope this helps!!!
Step-by-step explanation:
