Question

What is the center and radius of the circle? (x-3)2 + y² = 4

Answer 1

Answer:

center = (3, 0)

radius = 2

Step-by-step explanation:

Standard equation of a circle:  $\sf (x-h)^2+(y-k)^2=r^2$

(where (h, k) is the center of the circle and r is the radius)

Given equation:

$\sf (x-3)^2+y^2=4$

Rewrite in standard form:

$\sf \implies (x-3)^2+(y-0)^2=2^2$

Therefore

• center = (3, 0)
• radius = 2