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Paladinen [302]
3 years ago
5

Please help me to work this out

Mathematics
1 answer:
qaws [65]3 years ago
5 0

Answer:

P ( not white ball) = 2/3

Step-by-step explanation:

If there are 10 blue balls and 10 black balls and 10 white balls,

10+10+10 = 30 total balls

P(white ball) = white balls/ total balls

                     = 10/30

                      = 1/3

P (not getting a white ball) = not white/ total

                                            = (blue + black)/ total

                                              = (10+10)/30

                                                 =20/30

                                                    2/3

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The product of -3x and (2x+5) is …​
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- 3x \times (2x + 5) \\  =  - 3x \times 2x +  - 3x \times 5 \\  =  - 6x ^{2}  - 15x

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꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

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3 years ago
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Determine the area enclosed by y=2x+3, the x-axis and the ordinates x=3 and x=4​
jok3333 [9.3K]

Answer:

\displaystyle \int\limits^4_3 {2x + 3} \, dx = 10

General Formulas and Concepts:
<u>Calculus</u>

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:                                                           \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                 \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                     \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Property [Addition/Subtraction]:                                                   \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                               \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

y = 2x + 3

<em>x</em>-interval [3, 4]

<em>x</em>-axis

<em>See attachment for graph.</em>

<u>Step 2: Find Area</u>

  1. Substitute in variables [Area of a Region Formula]:                               \displaystyle A = \int\limits^4_3 {2x + 3} \, dx
  2. [Integral] Rewrite [Integration Property - Addition/Subtraction]:           \displaystyle A = \int\limits^4_3 {2x} \, dx + \int\limits^4_3 {3} \, dx
  3. [Integrals] Rewrite [Integration Property - Multiplied Constant]:           \displaystyle A = 2 \int\limits^4_3 {x} \, dx + 3 \int\limits^4_3 {} \, dx
  4. [Integrals] Integrate [Integration Rule - Reverse Power Rule]:               \displaystyle A = 2 \bigg( \frac{x^2}{2} \bigg) \bigg| \limits^4_3 + 3(x) \bigg| \limits^4_3
  5. [Integrals] Integrate [Integration Rule - FTC 1]:                                       \displaystyle A = 2 \bigg( \frac{7}{2} \bigg) + 3(1)
  6. Simplify:                                                                                                     \displaystyle A = 10

∴ the area bounded by the region y = 2x + 3, x-axis, and the coordinates x = 3 and x = 4 is equal to 10.

---

Learn more about integration: brainly.com/question/26401241

Learn more about calculus: brainly.com/question/20197752

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

3 0
2 years ago
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Romashka [77]

Answer:

That is correct

Step-by-step explanation:

When doing the math you can find that b and d are correct

8 0
3 years ago
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One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi
Elena L [17]

-16.8 = m(4)

-16.8 / 4 = -4.2

So the constant rate is -4.2.

Hope this Helps!!

4 0
3 years ago
Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit
Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is 2

Part 2) The vertex is the point (1,8)

Part 3) The equation of the axis of symmetry is x=1

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is y=2x^{2}-4x+10

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

x=h

In this problem we have

y=2(x-1)^{2}+8 -----> this is the equation in vertex form of a vertical parabola

The value of a=2

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point (1,8)

so

(h,k)=(1,8)

The equation of the axis of symmetry is x=1

The equation of a vertical parabola in standard form is equal to

y=ax^{2}+bx+c

Convert vertex form in standard form

y=2(x-1)^{2}+8

y=2(x^{2}-2x+1)+8

y=2x^{2}-4x+2+8

y=2x^{2}-4x+10

see the attached figure to better understand the problem

7 0
3 years ago
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