Answer:
no
Step-by-step explanation:
532,532 would be the answer
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
Answer:
The probability that Dr. Agor made his free throw is 40%.
Step-by-step explanation:
Given the fact that Dr. Agor usually converts his free throws with a probability of 0.4, to determine the percentage of probability that he will convert his free throw, the following calculation has to be performed:
0.4 x 100 x 1 = X
40 x 1 = X
40 = X
Therefore, Dr. Agor has a 40% chance of making his free throw.
For this case we have:
: Let the variable representing the first odd number
: Let the variable representing the consecutive odd number at x.
According to the statement we have:
We found the solution by factoring:
We look for two numbers that, when multiplied, result in -63 and when added, result in 2. These numbers are +9 and -7.
Thus, we have:
Therefore the solutions are:
We choose the positive value, so we have:
Answer:
The largest number is 9
