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KATRIN_1 [288]
2 years ago
10

Scale drawing: a rectangle with length 4 feet and width 3.75 feet. Initial dimensions: a rectangle with length 24 feet and width

15 feet. New dimensions: a rectangle with length 20 feet and width 18.75 feet.
Abdul planned a pool to be 24-feet long. To fit in his yard, however, the pool can only be 20-feet long. Abdul’s ratio and work is below. Where did he make an error?

StartFraction 24 feet divided by 6 over 20 feet divided by 6 EndFraction = StartFraction 4 over 3 EndFraction
Abdul’s work is correct.
Abdul should have divided by 5, not 6.
Abdul should have divided by 4, not 6.
This problem has no change in the scale factor.


Please help! Fast! Thank you <3
Mathematics
1 answer:
frutty [35]2 years ago
3 0

Answer:

C

Step-by-step explanation:

I think imsorry if I'm wrong

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kirill [66]

Answer:

D

Step-by-step explanation:

diameter of 1 circle = 21.3/3= 7.1

radius of 1 circle= 7.1/3=3.55

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area of 3 circle= 39.57×3=118.72

therefore,area of shaded portion= area of 3 circle =118.72

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The length of a rectangle 1.6 times longer with the sum of width and length being 130 feet
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<span>Let  be the length, and  be the width.
If the length is 1.6 times the width, then

If the sum of the length and with (in feet) is 130, then
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3 years ago
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Find the 7th term of the number pattern of general term 5n-4​
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Answer:

Step-by-step explanation:

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4 0
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Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
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