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Crazy boy [7]
2 years ago
11

Solving quadratic equations is one of the main topics of this unit. Some quadratic equations can be solved with only one method,

some can be solved with multiple methods, and some can’t be solved at all. Think about a task in your daily life that can be accomplished in a variety of ways. How do you decide the best course of action for accomplishing that task? How is this process like choosing a method for solving a quadratic equation that can be solved in multiple ways?
Mathematics
1 answer:
ICE Princess25 [194]2 years ago
7 0

The method for solving a quadratic equation, just like the way we choose to cook depends on the nature of the equation facing us.

<h3>Quadratic equation</h3>

A quadratic equation is an equation of the sort f(x) = ax^2 + bx + c = 0. The methods of solving a quadratic equation include;

  • Factorization
  • Formula method
  • Completing the square
  • Graphical method

Just like in daily life, the method chosen for solving a quadratic equation depends on the need of the moment. If I want to cook, I could use a microwave, a gas stove or  firewood. The method I choose depends on the kind of food I want to prepare.

Similarly, the method for solving a quadratic equation depends on the nature of the equation facing us.

Learn more about quadratic equation: brainly.com/question/2263981

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Answer:

1st blank: 4

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Step-by-step explanation:

-2²=4

4(-2)=-8

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4 + -8 = -4

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2 years ago
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I’m a little confused with this? Can someone walk me through this?
mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

The distance between the two coordinates = distance of d;

distance \ between \ two \ coordinates = \sqrt{(x_2-x_1)^2 \ + \ (y_2-y_1)^2} \\\\d =  \sqrt{(-3-0)^2 \ + \ (-5-0)^2}\\\\d = \sqrt{9 \ + \ 25} \\\\d = \sqrt{34} \\\\d = 5.83\\\\d = 5.8

Option A is correct

6 0
3 years ago
One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit
Rasek [7]

We are given

N=\frac{11}{60} (F-32)

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

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60N=11 (F-32)

step-2:

Divide both sides by 11

\frac{60N}{11} =\frac{11(F-32)}{11}

\frac{60}{11}N =F-32

step-3:

Add both sides by 32

\frac{60}{11}N+32 =F-32+32

\frac{60}{11}N+32 =F

so, we get

F=\frac{60}{11}N+32................Answer

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Answer:

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Step-by-step explanation:

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