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Crazy boy [7]
2 years ago
11

Solving quadratic equations is one of the main topics of this unit. Some quadratic equations can be solved with only one method,

some can be solved with multiple methods, and some can’t be solved at all. Think about a task in your daily life that can be accomplished in a variety of ways. How do you decide the best course of action for accomplishing that task? How is this process like choosing a method for solving a quadratic equation that can be solved in multiple ways?
Mathematics
1 answer:
ICE Princess25 [194]2 years ago
7 0

The method for solving a quadratic equation, just like the way we choose to cook depends on the nature of the equation facing us.

<h3>Quadratic equation</h3>

A quadratic equation is an equation of the sort f(x) = ax^2 + bx + c = 0. The methods of solving a quadratic equation include;

  • Factorization
  • Formula method
  • Completing the square
  • Graphical method

Just like in daily life, the method chosen for solving a quadratic equation depends on the need of the moment. If I want to cook, I could use a microwave, a gas stove or  firewood. The method I choose depends on the kind of food I want to prepare.

Similarly, the method for solving a quadratic equation depends on the nature of the equation facing us.

Learn more about quadratic equation: brainly.com/question/2263981

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-3/4÷-1/2<br><br>pls help armieee​
PilotLPTM [1.2K]

Answer:

exact form : 3/2

decimal form 1.5

mixed number form 1 1/2

8 0
3 years ago
The table shows the outputs y for different inputs x:
Rasek [7]
Part A: Yes, the data represent a function. The definition of a function is a relation in which no value of x will have two different values of y.
(Every time you plug in 3 as x, you will always get 4 as y; it's ok if you plug in 3 and 5 as x and get the same y, you just can't get two different y's for one x; sorry, it is pretty confusing). None of the numbers in the table repeat, so we can safely say that the relation is a function.

Part B: All we have to do is plug in 11 for x in the function given to find the answer:
f(x)=5x-21\\f(x)=5(11)-21\\f(x)=55-21\\f(x)=34
In the table, y = 8 when x = 11, but in the function given, y = 34 when x = 11, so the function given is greater.

Part C: To find the answer to C, just plug in 99 for f(x), as it tells you to do:
f(x) = 5x-21\\99=5x-21\\99+21=5x-21+21\\120=5x\\120/5=5x/5\\24=x
5 0
3 years ago
Read 2 more answers
Can someone help me with this?
LekaFEV [45]
The constant variation for the relationship being shown is 4
3 0
2 years ago
Read 2 more answers
(x+3)²(65)=x(6)<br>Solve using quadric formula​
Angelina_Jolie [31]

Step 1: Simplify both sides of the equation.

  • 65x²+390x+585=6x

Step 2: Subtract 6x from both sides.

  • 65x²+390x+585−6x=6x−6x
  • 65x²+384x+585=0

For this equation: a=65, b=384, c=585

  • 65x²+384x+585=0

Step 3: Use quadratic formula with a=65, b=384, c=585

  • x=−b±√b2−4ac/2a
  • x=−(384)±√(384)2−4(65)(585)/
  • 2(65)
  • x=−384±√−4644/130

Therefore, There are no real solutions.

6 0
2 years ago
Read 2 more answers
Need help with this problem explain pls
Usimov [2.4K]
All sides of an equilateral triangle are equal, so all three sides are 9 cm.
To find h, use the pythagorean theorem. This requires use of only one right triangle, where we use b as our h.

a^2+b^2=c^2
(4.5)^2+b^2=(9)^2
(20.25)+b^2=(81)
b^2=(81/20.25) or 4
square root both sides
b=2
6 0
3 years ago
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