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3 years ago

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What happens when you celebrate halloween in spring matrix multipication

1 answer:

MariettaO [177]3 years ago

3 0

Answer:

his is the day that immediately proceeds the last and final spring sabbat, ... The fact that Beltane and Samhain happen in unison twice a year lends ... You know all those Halloween recipes you've been saving on Pinterest for years now? ... Halloween and Samhain product brands as you can all year long.

Step-by-step explanation:

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If its 10/16 what is answer as a decimal

Vedmedyk [2.9K]

Answer:

0.625 is a decimal and 62.5/100 or 62.5% is the percentage for 10/16.

Step-by-step explanation:

Please mark brainliest and have a great day!

3 0

3 years ago

Read 2 more answers

Logx+log6=69<br> Round to nearest tenth

ohaa [14]

Answer:

1

Step-by-step explanation:

5 0

2 years ago

A scientist begins with 250 grams of a radioactive substance. After 250 minutes, the sample has decayed to 32 grams. Rounding to

s2008m [1.1K]

Answer:

Part 1 : $A=250 e^{-0.008223t}$

Part 2 : Half life is 84 minutes ( approx )

Step-by-step explanation:

Part 1 : Suppose the function that shows the amount( in grams ) of the substance after t minutes,

$A=A_0 e^{kt}$

If t = 0 min, A = 250 grams,

$250=A_0 e^{0}$

$\implies A_0 = 250$

If t = 250, A = 32 grams,

$32 = A_0 e^{250k}$

$32 = 250 e^{250k}$

$0.128 = e^{250k}$

Taking ln both sides,

$\ln(0.128) = 250k$

$\implies k =\frac{\ln(0.128)}{250}=-0.008223$

Hence, the equation that shows this situation,

$A=250 e^{-0.008223t}$

Part 2 : If A = 250/2 = 125,

$125 = 250 e^{-0.008223t}$

$0.5 = e^{-0.008223t}$

Taking ln both sides,

$\ln(0.5) = -0.008223t$

$\implies t =\frac{\ln(0.5)}{-0.008223}\approx 84$

Therefore, the half life of the substance would be 84 minutes.

8 0

3 years ago

{Stop scrolling} this is not a question but I just wanted you to know that you are doing absolutely amazing and I am extremely p

Vanyuwa [196]

Thanks. I’m not struggling or anything but thanks for the kind words.

7 0

3 years ago

Read 2 more answers

Factorise and solve : x^3-x^2-4x+4

Alika [10]

(x - 1)(x - 2)(x + 2)

note that the sum of the coefficients 1 - 1 - 4 + 4 = 0

thus x = 1 is a root and (x - 1 ) is a factor

dividing x³ - x² - 4x + 4 by (x - 1)

x³ - x² - 4x + 4 = (x - 1)(x² - 4 ) (note (x² - 4 ) is a difference of squares )

x³ - x² - 4x + 4 = (x - 1)(x - 2)(x + 2)

(x - 1)(x - 2)(x + 2 ) =0

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

x + 2 = 0 ⇒ x = - 2

solutions are x = 1 or x = ± 2

6 0

3 years ago