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kozerog [31]
3 years ago
11

Apple sent a survey to some of their customers. Some people were sent the survey but did not finish it. What is the fewest numbe

r of people that could of been given the the survey if exactly 93.6% of people completed it? Hint: How could we determine if only one person could have completed it? Can we have partial people complete the survey?
Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

117

Step-by-step explanation:

since it's exactly 93.6%, it means it must be more than 100people as it can't be 93.6people/100people as a person cannot be less than 1. the lowest possible number of people therefore can only be 117/125people as when converted to a fraction, 93.6% = 93.6/100 but no decimals are allowed in fractions so 936/1000 and when reduced/simplified, we get 117/125 hence the answer is 117.

Topic: percentage-fraction conversion

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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In the freshman class, 62% of the students take math, 49% take science, and 38% take both science and math. what percentage take
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we are given

62% of the students take math

so,

n(M)=62

49% take science

n(S)=49

38% take both science and math

n(M∩S)=38

now, we can use union formula

n(M∪S)=n(M)+n(S) -n(M∩S)

now, we can plug values

and we get

n(M∪S)=62+49 -38

n(M∪S)=73

so,

the percentage takes at least one science or math course is 73%..........Answer

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3 years ago
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5(x+3)........ ...........

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8 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

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3 years ago
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