we are given
62% of the students take math
so,

49% take science

38% take both science and math
n(M∩S)=38
now, we can use union formula
n(M∪S)=n(M)+n(S) -n(M∩S)
now, we can plug values
and we get
n(M∪S)=62+49 -38
n(M∪S)=73
so,
the percentage takes at least one science or math course is 73%..........Answer
Answer:
5(x+3)........ ...........
I think its 1/2…hope this helps id it dont then.....:\¯\_(ツ)_/¯
Y=(-9--4) + (-3--7)
ALWAYS USE PEMDAS FORMULAS.
Solution :
Given that :
The radius of circle A = 6 cm
The radius of circle C = 4 cm
In circle A

The length of arc EF = 

= 14.653 cm
In circle C

The length of arc GH = 

= 9.769 cm
Therefore,
The length of EF is 14.653 cm
The length of GH is 9.769 cm
The length of EF is 1.5 times the length of GH
i.e. 14.653 = 1.5 x 9.769
14.653 = 14.653
Hence proved.