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2 years ago

Is ( – 1, – 5) a solution to this system of equations? 7x+2y=13 4x+4y=14

Mathematics

1 answer:

Rus_ich [418]2 years ago

5 0

Answer:

yes

Step-by-step explanation:

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Please answer!! 20 points ASAP

lidiya [134]

Answer:

The length of VI to the nearest tenth is 4 cm

Solution:

The plot is like a quadrilateral and the fences are built on the diagonal

We know that for quadrilateral both the diagonals are in same height,

So as per the picture, $\mathrm{GH}=\mathrm{Fl}$

Now we know that $\mathrm{GV}=6.55 cm; \mathrm{FV}=5.84 cm; \mathrm{VH}=3.27 cm$

Hence,

$GH = FI$

$\Rightarrow GV + VH = VI + VF$

$\Rightarrow 6.55 + 3.27 = VI + 5.84$

$\Rightarrow VI = 6.55 + 3.27 - 5.84$

$\Rightarrow VI = 3.98$

Rounding off:

If the number that we are rounding is followed by 5 to 9, then the number has to be increased to the next successive number.

If the number that we are rounding is followed by 1 to 4, then the number has to remain the same.

Here the number to be round off is 3.98, 9 belongs to the first category stated above. So, 3 is increased to 4.

Hence, the length of VI = 4 cm.

7 0

3 years ago

Write 750 g as a fraction of 5 kg. Give your answer in its simplest form.

Valentin [98]

Answer:

3/20 is the answer.......

8 0

2 years ago

Hey guys! Sorry to bother but I need help with these. 5th grade math, will give brainliest! (If you see multiple questions by me

Delicious77 [7]

Answer:

1/36 and 1/28

Step-by-step explanation:

i believe this is the answer as you should divide the denomonator by the answer as you cannot divide the numerator.

6 0

2 years ago

Solve for x. x / 4 ≥ - 8

MariettaO [177]

Answer:

$x \geqslant ( - 32) \: \: \: \: or \: \: \: \: ( - 32) \leqslant x$

Step-by-step explanation:

$\frac{x}{4} \geqslant - 8 \\ x \geqslant - 8 \times 4 \\ x \geqslant (- 32) \\$

3 0

3 years ago

A jet plane has a takeoff speed of vto = 75 m/s and can move along the runway at an average acceleration of 1.3 m/s2. If the len

pishuonlain [190]

Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m

time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s

the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s

Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.

6 0

3 years ago

Read 2 more answers