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Tems11 [23]
2 years ago
6

Graph the line y = 3x

Mathematics
2 answers:
ollegr [7]2 years ago
7 0

Answer:

literally google graphing calculator and type 3x

Basile [38]2 years ago
3 0

Answer:

There you go! Have a good rest of your day

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5+2+2(5)+3=4(5) plr help me​
juin [17]

Answer:

5+2+2(5)+3=4(5)

simplify

5+2+10+3=20 and  4(5)=20  

20=20

6 0
3 years ago
Read 2 more answers
The rectangle is three times its width.
Airida [17]

Answer:

Length= 30 in

Width= 10 in

Step-by-step explanation:

Let the width of the rectangle be x in.

Length of rectangle

= 3 (width)

= 3x

Perimeter of rectangle= 2(length) +2(width)

80= 2(3x) +2(x)

80= 6x +2x

8x= 80 <em>(</em><em>simplify</em><em>)</em>

x= 80 ÷8 <em>(</em><em>÷</em><em>8</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

x= 10

Thus width of rectangle= 10 in

Length of rectangle

= 3(10)

= 30 in

7 0
3 years ago
HELp Help Help... fnljwbfjwopfowq
makkiz [27]
Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x-(3*x^3+8*x^2+5*x-7)=0
Step by step solution :Step 1 :Equation at the end of step 1 : x-((((3•(x3))+23x2)+5x)-7) = 0 Step 2 :Equation at the end of step 2 : x - (((3x3 + 23x2) + 5x) - 7) = 0 Step 3 :Step 4 :Pulling out like terms :
4.1 Pull out like factors :
-3x3 - 8x2 - 4x + 7 =
-1 • (3x3 + 8x2 + 4x - 7)
Checking for a perfect cube :
4.2 3x3 + 8x2 + 4x - 7 is not a perfect cube
Trying to factor by pulling out :
4.3 Factoring: 3x3 + 8x2 + 4x - 7
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3x3 - 7
Group 2: 8x2 + 4x
Pull out from each group separately :
Group 1: (3x3 - 7) • (1)
Group 2: (2x + 1) • (4x)

Please 5 star and like. Appreciated
8 0
3 years ago
Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.
Serga [27]
\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ 6}}\quad ,&{{ -4}})\quad &#10;%  (c,d)&#10;&({{ 2}}\quad ,&{{ -7}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}
5 0
3 years ago
If TV ≅ WV and UV ≅ XV, then which congruency theorem shows that ΔTUV ≅ ΔWXV ?
VashaNatasha [74]

Answer:

Option (2).

Step-by-step explanation:

In the figure attached,

Given : TV ≅ WV and UV ≅ XV

To prove: ΔTUV ≅ ΔWXV

                Statements                  Reasons

1). TV ≅ WV                              1). Given

2). UV ≅ XV                             2). Given

3). ∠XVW ≅ ∠TVU                  3). Reflexive property

4). ΔTUV ≅ ΔWXV                  4). SAS (Side - angle - side) property of                                                             congruence

Therefore, Option (2) will be the answer.

5 0
3 years ago
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