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Mashutka [201]
2 years ago
7

Kindly solve this question

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
3 0

Answer:

x=-1/7

Step-by-step explanation:

\frac{3x-1}{3} -\frac{2x}{x-1} =x

\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x

\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}

\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}

3x^2-10x+1=3x^2-3x

-10x+1=-3x

-7x=1

x=-1/7

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Answer:

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Step-by-step explanation:

Given expression = x + 15% of x

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Use two 2-Column proofs to show that either diagonal of a rectangle will create two congruent triangles?
tangare [24]
<span>Given: Rectangle ABCD 
Prove: ∆ABD≅∆CBD 
Solution:
                      
           <span> Statement                                       Reason 
</span>
  ABCD is a parallelogram          Rectangles are parallelograms since the                                                          definition of a parallelogram is a quadrilateral                                                    with two pairs of parallel sides.

Segment AD = Segment BC       The opposite sides of a parallelogram are     Segment AB = Segment CD       congruent. This is a theorem about the                                                              parallelograms.

</span>∆ABD≅∆CBD                             SSS postulate: three sides of ΔABD is                                                           equal to the three sides of ∆CBD<span>


</span><span>Given: Rectangle ABCD 
Prove: ∆ABC≅∆ADC
</span>Solution:
                      
           <span> Statement                                       Reason 
</span>
    Angle A and Angle C                 Definition of a rectangle: A quadrilateral     
        are right angles                      with four right angles.

        Angle A = Angle C                 Since both are right angles, they are                                                                  congruent

Segment AB = Segment DC       The opposite sides of a parallelogram are     Segment AD = Segment BC       congruent. This is a theorem about the                                                              parallelograms.

            ∆ABC≅∆ADC                   SAS postulate: two sides and included                                                         angle of ΔABC is congruent to the two                                                         sides and included angle of ∆CBD
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