2 years ago

Kindly solve this question

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

Answer:

x=-1/7

Step-by-step explanation:

$\frac{3x-1}{3} -\frac{2x}{x-1} =x$

$\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x$

$\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x$

$\frac{3x^2-10x+1}{3x-3} =x$

$\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}$

$\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}$

$3x^2-10x+1=3x^2-3x$

$-10x+1=-3x$

$-7x=1$

$x=-1/7$

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