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NARA [144]
3 years ago
12

Hello I hope you have a wonderful day can you pls help me out it I will fail

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0
A. Independent goes on the x axis and dependent goes on the y axis
B. It shows his or hers miles per hour or mph or distance they run in a hour

Hope this helps have a great Monday ❤️
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A cable installer charges $30.00 per hour plus a $50.00 service charge. Your father's firm hires him to hookup his company's int
vladimir1956 [14]
30*8.5=255 255+50=$305
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3 years ago
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Which could be the graph of the equation below<br> Y = 4 - x
Gelneren [198K]
The graph that has a slop of -1 and the y-interecept is 4
that graph is the 1st picture and top one
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3 years ago
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PLEASE ANSWER picture shown
Alexxx [7]
\frac{x}{2} + \frac{7}{9x}
= \frac{x*9x}{2*9x} + \frac{7*2}{9x*2}
= \frac{9x^2}{18x} + \frac{14}{18x}
= \frac{9x^2+14}{18x}

Therefore the answer is B.

Hope this helps !

Photon
5 0
3 years ago
Karen runs a print shop that makes posters for large companies. It is a very competitive business. The market price is currently
kumpel [21]
AFC = FC / Quantity printed 

<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>

<span>ATC = TC / Quantity printed </span>

<span>where TC = FC + Variable C * Quantity printed </span>

<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>

<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>

<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
7 0
3 years ago
plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
3 years ago
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