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2 years ago

Hello I hope you have a wonderful day can you pls help me out it I will fail

Mathematics

1 answer:

ASHA 777 [7]2 years ago

5 0

A. Independent goes on the x axis and dependent goes on the y axis
B. It shows his or hers miles per hour or mph or distance they run in a hour

Hope this helps have a great Monday ❤️

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What is the solution of -6 + a = 22? A 28 B. -28 0 C. 16 D. -16

KatRina [158]

Answer:

A.28

Step-by-step explanation:

Substitute a with 28 so:

-6+28=22

Then simplify the equation:

22=22

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2 years ago

A grocery store stocks shelves with 100 cartons of strawberries before the store opens. For the first 3 hours the store is open,

ehidna [41]

Answer:

80 - 30(first hour )=50

50-0(2nd hour)=50

50-20=30

30-20=10

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2 years ago

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Taya2010 [7]

Answer:

Step-by-step explanation:

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3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

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3 years ago

Segment BC is a midsegment of triangle TUV. What is the length of segment VC? (A)a (B)2b (C)b (D)c

Ganezh [65]

It would be twice whatever the midsegment equals.

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3 years ago