Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Answer: 10y
Step-by-step explanation: All variables equal one unless assigned a specific answer. So It is basically 9y+1
9y+1=10y
Final Answer: 10y
Hope this helps! :D
Answer:
Rv and EA
Step-by-step explanation:
Because ik
Answer:
DE ≈ 16.1, ∠E ≈ 60.3°, ∠D ≈ 29.7°
Step-by-step explanation:
use pythagorean theorem:
DE² = 8² + 14² => DE = √8² + 14² ≈ 16.1
use inverse tangent function:
∠E = 
(14/8) ≈ 60.3°
∠D = (8/14) ≈ 29.7°
