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MrRa [10]
3 years ago
10

Im horrible at math plz help

Mathematics
2 answers:
atroni [7]3 years ago
5 0

Answer:

Sorry I am a little late but your answer is <u><em>4 9/16.</em></u>

Hope this helps :)

Alex73 [517]3 years ago
4 0

Answer: 4.5625

Step-by-step explanation: use pedmas

Parenthesis

Exponents

Division

Multiplication

Addition

Subtraction

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2 Points<br> What is the slope of the line shown below?<br> (2,2) 4,8
Vladimir79 [104]

Answer:

3

Step-by-step explanation:

Slope =y2−y1 divided to x2−x1

8−2

4−2

6/2

= 3

Hope this helped :)

Have a good one

5 0
3 years ago
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Two grocery stores are having deals on tomatoes. Sally's Grocery is selling 10 tomatoes for $6.30. Sweet Supermarket is selling
iragen [17]

Answer:

Step-by-step explanation:

Calculate price per unit:

7/5.10= $1.37

So the answer is the store selling 10 tomatoes for $6.30 is the lower unit price

The tomoatoes if they were sold at Sally’s instead would cost $4.41

4 0
2 years ago
EXPERT HELP EXPLAIN THE ANSWER:
KengaRu [80]

Answer: Its B!!!

Step-by-step explanation:

4 0
3 years ago
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Bob ate 12 cookies over the past two days. Assume he ate the same amount of cookies each day. How many cookies did Jonathan eat
docker41 [41]

Answer:

Its 6 cookies per day

Step-by-step explanation:

12/2=6 6 cookies per day

7 0
2 years ago
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For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right&#10;

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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