You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Answer:
Solve it
Explain:
1
Combine multiplied terms into a single fraction
1
4
+
1
8
=
\frac{1}{4}x+18=x
41x+18=x
1
4
+
1
8
=
Answer:
(x+3) and (x-6) are factors
Step-by-step explanation:
The given expression is :
x²-3x-18
We need to find the factors of the above expression.
We can solve it using middle term splitting. We find two integers such that there product is -18 and sum is -3. These two numbers can be -6 and 3.
x²-3x-18 = x²-6x+3x-18
= x(x-6)+3(x-6) [taking common terms]
= (x+3) (x-6)
Hence, the factors of the above expression is (x+3) and (x-6).
Answer:
6
Step-by-step explanation:
numbers/variables raised to the first power are equal to themselves
