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asambeis [7]
2 years ago
5

A relief worker needs to divide 1350 bottles of water and 144 cans of food into boxes that each contain the same number of items

.​ Also, each box must contain the same type of item​ (bottled water or canned​ food). What is the largest number of relief supplies that can be put in each​ box?
Mathematics
1 answer:
Setler79 [48]2 years ago
8 0

The largest number of relief supplies that can be put in each box is 75 bottles and 8 cans of food respectively.

<h3>How to find highest common factor</h3>

The factors of:

1350 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 27, 30, 45, 50, 54, 75, 90, 135, 150, 225, 270, 450, 675 and 1350.

144 = 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144.

  • The highest common factor of 1350 and 144 is 18

1350 bottles / 18

= 75 bottles per box

144 cans of food / 18

= 8 cans of food per box

So, there 18 boxes of items, each containing 75 bottles and 8 cans of food respectively.

Learn more about highest common factor:

brainly.com/question/120215

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Step-by-step explanation:

we know ,

area of circle =πr^2

hence we get from the figure that the diameter of circle is 19 cm and we can find radius

r=d/2

r=18/2=9cm

area of semicircle =πr^2/2

area of Semi circle equals to =22*(9)^2/7/2

=127.2857143

3 0
3 years ago
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Suppose that a rectangular piece of glass has a perimeter of 20 meters. If we multiply both its length and its width by 4, what
goldenfox [79]

Answer:

Answer B is the correct answer

Step-by-step explanation: :)

3 0
3 years ago
Question 6<br> Find the slope of the line passing through the points (11,-5) and (11,6)
zimovet [89]

There are two ways to approach this.

Option #1:

Use the slope formula m = \dfrac{y_2-y_1}{x_2-x_1}.

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That value is undefined, so the slope is undefined.

Option #2:

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3 0
2 years ago
Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

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Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

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From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

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⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

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Hence, the point of maximum growth is at x=0.82


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