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NikAS [45]
2 years ago
10

Answer number 1 please. Thank you.

Mathematics
1 answer:
shutvik [7]2 years ago
7 0
S=9 because each length in the second figure is being multiplied by 3
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A set of middle school student heights are normally distributed with a mean of 150150150 centimeters and a standard deviation of
adell [148]

Answer:

71.57% of student heights are lower than Darnell's height

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 150, \sigma = 20

Darnell has a height of 161.4 centimeters. What proportion of student heights are lower than Darnell's height?

This is the pvalue of Z when X = 161.4.

Z = \frac{X - \mu}{\sigma}

Z = \frac{161.4 - 150}{20}

Z = 0.57

Z = 0.57 has a pvalue of 0.7157

71.57% of student heights are lower than Darnell's height

5 0
3 years ago
. What is the sum of the first 4 multiples of 3?​
KIM [24]
Answer is 30 .I think it’s will help you
6 0
3 years ago
Read 2 more answers
What is the probability of rolling a 10 out a 12 sided die
lions [1.4K]
1/12

There is 1 side of the die that has a ten on it and 12 sides in total. Therefore, there is a 1/12 chance of rolling a ten on this die.
5 0
3 years ago
22. A liver cell is about 20 um in diameter. How many liver cells would it take to form an end to end chain 10 in long?
34kurt

The number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells

<h3>Calculating quantity</h3>

From the question, we are to determine how many liver cells it would take to form an end to end chain 10 in long

First, we will convert 10 in to meters

1 inch = 0.0254

∴ 10 inches = 0.254 m

From the giving information,

A liver cell is about 20 μm in diameter

∴ The number of liver cells it would take to form an end to end chain 10 in long = 0.254 m / 20 μm

= 0.254 m / (20 ×10⁻⁶) m (NOTE: 1μm = 10⁻⁶m)

= 12700

Hence, the number of liver cells it would take to form an end to end chain 10 in long is 12,700 liver cells

Learn more on Calculating quantity here: brainly.com/question/2021001

#SPJ1

8 0
2 years ago
Show me the steps to solve and the solution y-2&gt;1/2(x-2)
aev [14]
<span>y-2>1/2(x-2) can be expanded as follows:  y - 2 > (1/2)x - 1

Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

Add 4 to both sides:   2y > x + 2

Div. both sides by 2:    y > (1/2)x + 1   (answer)</span>
4 0
4 years ago
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