All categories

3 years ago

What is the solution to the system. use the substitution method. y 7 = 3x?

1 answer:

8 0

You can use an input table x is the input and y is the output.
3(x) (y)7
3(1)=3 (3)7=21
........................................
so on

You might be interested in

Can not be bothered to write the question so ima just attach it

stellarik [79]

Use desmos graphing calculator, for visuals. It's easy to use as well.

A is 0 (zero)

(1x1 + 2x1 - 3)

B) D ( lies on 1 on our x-axis)

C) This tells you to draw a line at zero on the y-axis, a horizontal line BTW & read off the x values, where the line touches the pink graph/diagram.

y=x^2+2x-3 is the similar to x^2+2x-3=0 because the letter y now represents zero. So, that's why we draw the line y=0 (a horizontal line at zero). Then, use it to find the x values.

Thus, x = - 3 & x = 1

Hope this helps!

6 0

2 years ago

You earn $9 per hour. Which equation shows the relationship between the time worked in hours, t, and the money earned in dollars

luda_lava [24]

Answer:

m=9t

Step-by-step explanation:

to figure out how much money you earned, you have to multiply how long you worked by the amount you get paid

6 0

3 years ago

4 times as much money as $5

lesantik [10]

The answer is 4x5=20

4 0

3 years ago

Read 2 more answers

Number 8 please! It's urgent

kykrilka [37]

T chart but thats all i can think of

3 0

3 years ago

Find the perimeter of each of the two non congruent triangles where a=15,b=20 and a=29

Alborosie

Answer:

b. about 63.9 units and 41.0 units

Step-by-step explanation:

In question ∠a= 29° and Side of a= 15 and b= 20

Using sine rule of congruence of triangle.

⇒ $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

⇒ $\frac{15}{Sin 29} = \frac{20}{sin B}$

Using value of sin 29°

⇒ $\frac{15}{0.49} = \frac{20}{sin B}$

Cross multiplying both side.

⇒ Sin B= $\frac{20\times 0.49}{15} = 0.65$

∴ B= 41°

Now, we have the degree for ∠B= 41°.

Next, lets find the ∠C

∵ we know the sum total of angle of triangle is 180°

∴∠A+∠B+∠C= 180°

⇒ $29+41+B= 180$

subtracting both side by 70°

∴∠C= 110°

Now, again using the sine rule to find the side of c.

$\frac{b}{SinB} = \frac{c}{SinC}$

⇒ $\frac{20}{sin41} = \frac{C}{sin110}$

Using the value of sine and cross multiplying both side.

⇒ C= $\frac{20\times 0.94}{0.65} = 28.92$

∴ Side C= 28.92.

Now, finding perimeter of angle of triangle

Perimeter of triangle= a+b+c

Perimeter of triangle= $(15+20+28.92)= 63.9$

∴ Perimeter of triangle= 63.9 units

7 0

3 years ago