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Semenov [28]
3 years ago
7

6-^3 ------ 6-^4 A) 6-7 B) 6-1 C) 61 D) 612

Mathematics
2 answers:
Bad White [126]3 years ago
5 0
The answer should be 6 I.e 6^1 as with indices rules you need to subtract the powers (-3-(-4)) which equals 1
Irina-Kira [14]3 years ago
5 0

Answer:

6^1

Step-by-step explanation:

Use\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{6^{-3}}{6^{-4}}=6^{-3-(-4)}=6^{-3+4}=6^1

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Please help with this Math Question...
Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 |   1   4   7   6

   <u>|   ↓  -2  -4  -6</u>

       1    2    3   0 ← remainder is 0 so x = -2 is a root  ⇒  (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}

x=\dfrac{-2\pm\sqrt{4-12} }{2}

x=\dfrac{-2\pm\sqrt{-8} }{2}

x=\dfrac{-2\pm2i\sqrt{2}}{2}

x = -1 \pm i\sqrt{2}

x = -1 + i\sqrt{2}       x = -1 - i\sqrt{2}

x - (-1 + i\sqrt{2})=0       x - (-1 - i\sqrt{2})=0

The factors are:

(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]




5 0
2 years ago
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