We know that
tan²(A)+1 = sec²(A)--------> tan²(A)= sec²(A)-1
tan²(A)= (4/3)²-1------> tan²(A)=16/9-1-----> 7/9
tan²(A)=7/9
if the angle A is in the IV quadrant
then
tan (A) is negative
therefore
tan (A)=-√(7/9)-----> tan (A)=-√7/3
so
cot (A)=1/tan(A)------> cot (A)=-3/√7----> -(3/7)*√7
the answers are
a) the identity is tan²(A)= sec²(A)-1
b) tan (A)=-√7/3
Answer:
75º
165º
15º
255º
Explanation:
75º because half a circle is equal to 180º.
You know it is 165º because of the same reason.
You get the 15º from knowing that opposite angles are equal.
255º is a case of adding the angles.
Answer:
4/10= 0.4
3 1/10= 3.1
7/10= 0.7
6 5/10= 6.5
9/10= 0.9
Step-by-step explanation:
The first thing to do in this case is to find the volume of the sphere.
We have then:
V = (4/3) * (pi) * (r ^ 3)
V = (4/3) * (pi) * ((4) ^ 3)
v = 268 in ^ 3
Then, the but of the sphere will be given by:
W = (0.075) * (268)
W = 20
Answer:
the weight of the sphere, to the nearest pound is:
A) 20
