Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
C. 60%
The probability that a person surveyed is 40 or older and gets the news by reading the paper is 60%.
Step-by-step explanation:
In our case, we have to find the probability of a person getting their news by reading the paper. But we are given with a condition that the person must be 40 or older.
The survey is conducted among 80 people.
Number of people aged 40 or older = 40
No of people aged 40 or older and read paper = 24
Probability formula is the ratio of number of favorable outcomes to the total number of possible outcomes.
Probability of a person aged 40 or older reads a paper =
(No. of People aged 40 or older and read paper)/(No. of people aged 40 or older)
= 24/40
= 0.6
= 60%
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1) Would be c+15 because you can combine 19-4
2) Would be m+2 because you can combine 12-10
The equation to show the depreciation at the end of x years is
Data;
- cost of machine = 1500
- annual depreciation value = x
<h3>Linear Equation</h3>
This is an equation written to represent a word problem into mathematical statement and this is easier to solve.
To write a linear depreciation model for this machine would be
For number of years, the cost of the machine would become
This is properly written as
where x represents the number of years.
For example, after 5 years, the value of the machine would become
The value of the machine would be $500 at the end of the fifth year.
From the above, the equation to show the depreciation at the end of x years is f(x) = 1500 - 200x
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Answer:
x < 6
Step-by-step explanation:
Subtract 4 form both sides
Multiply both sides by 3
