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ratelena [41]
2 years ago
6

Please answer all correctly !!

Mathematics
1 answer:
nexus9112 [7]2 years ago
3 0

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 1</u>

To convert from polar to Cartesian coordinates, recall that (x,y)=(r\:cos\theta,r\:sin\theta), thus, (x,y)=(6\:cos\frac{5\pi}{6},6sin\frac{5\pi}{6})=(6(-\frac{\sqrt{3}}{2}),6(\frac{1}{2}))=(-3\sqrt{3},3)

Therefore, C is the correct answer

<u>Problem 2</u>

Convert from polar to Cartesian coordinates:

(x,y)=(-5\:cos\frac{2\pi}{3},-5\:sin\frac{2\pi}{3})=(-5(-\frac{1}{2}),-5(\frac{\sqrt{3}}{2}))=(\frac{5}{2},\frac{-5\sqrt{3}}{2})

Therefore, U is the correct answer

<u>Problem 3</u>

Since r=\sqrt{x^2+y^2}, then r^2=x^2+y^2. Don't also forget to use the substitution x=r\:cos\theta:

x^2+y^2-7x=0\\\\r^2-7rcos\theta=0\\\\r(r-7cos\theta)=0\\\\r-7cos\theta=0\\\\r=7cos\theta

Therefore, B is the correct answer

<u>Problem 4</u>

<u />r=(tan\theta)(sec\theta)\\\\r=(\frac{sin\theta}{cos\theta})(\frac{1}{cos\theta})\\ \\\frac{r^2}{r}=(\frac{rsin\theta}{rcos\theta})(\frac{r}{rcos\theta})\\ \\\frac{x^2+y^2}{\sqrt{x^2+y^2}}=(\frac{y}{x})(\frac{\sqrt{x^2+y^2}}{x})\\ \\x^2+y^2=\frac{y(x^2+y^2)}{x^2}\\ \\1=\frac{y}{x^2}\\\\x^2=y

Therefore, A is the correct answer

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