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melamori03 [73]
3 years ago
13

Skyler goes to a school which has 1000 students in it. She asks 40 random students whether they like the new 8.30am start to the

day. 30 of them say "no" they do not like it. Use the information to estimate how many students in the whole school dislike the 8.30am start
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

100/40=25

25*30=750

so 750 students would dislike the new starting time.

I really hope this was correct and helpful. I tried my best.

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What is the equation of the function represented by this graph?
gayaneshka [121]

Answer:

\displaystyle g(x) = -(x + 2)(x - 4)

Step-by-step explanation:

First, look at the graph to determine whether it opens down or up, which in this case is <em>down</em>, so you insert a negative in front of the expression. Next, locate your <em>x-intercepts</em> [<em>zeros</em> (where the graph insects the x-axis)]. You will see that the graph intersects \displaystyle [-2, 0] and \displaystyle [4, 0], so what you do is insert the zeros' OPPOCITES into the equation because according to the vertex equation, \displaystyle y = A[x - h]^2 + k, that negative in front of \displaystyle h gives you the OPPOCITE outcome, so be careful.

I am joyous to assist you at any time.

6 0
2 years ago
Pleaseeee hellllppp thanks !
DaniilM [7]

Answer:

5.the rental all cost per day is 74-55.5=18.5 per day

Step-by-step explanation:

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4 0
3 years ago
Help needed here please help
bazaltina [42]

Answer:

g(f(x))= (x+3)(x+3)

Step-by-step explanation:

f(x) =x² + 6x +7

g(x)= x + 2

1st Step: Substitute the x in g(x) =x + 2 by the value of f(x)

g(f(x))= (x² + 6x +7) + 2

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2nd Step: Simplify

g(f(x))= x² + 6x + 9

g(f(x))= (x+3)(x+3)

4 0
2 years ago
A box is to be constructed with a rectangular base and a height of 5 cm. If the rectangular base must have a perimeter of 28 cm,
maw [93]
Perimeter = 2(width+length) =28
Let x=width of base, then length of base = (28/2)-x = 14-x
Volume of box = length*width*height
=x(14-x)*5 = 5x(14-x)


3 0
3 years ago
Read 2 more answers
Hello, Can I get some help with #30 a and b, please? Don't forget to show your work.
Murljashka [212]

Answer:

a. dy/dx = -2/3

b. dy/dx = -28

Step-by-step explanation:

One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.

a. x'·y^3 +x·(3y^2·y') = 0

y'/x' = -y^3/(3xy^2) = -y/(3x)

For the given point, this is ...

dy/dx = -2/3

___

b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'

y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)

y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)

For the given point, this is ...

dy/dx = 2(1 -0 +27)/(0 +0 -2)

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_____

The attached graphs show these to be plausible values for the derivatives at the given points.

6 0
2 years ago
Read 2 more answers
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