Answer:

Step-by-step explanation:
First, look at the graph to determine whether it opens down or up, which in this case is <em>down</em>, so you insert a negative in front of the expression. Next, locate your <em>x-intercepts</em> [<em>zeros</em> (where the graph insects the x-axis)]. You will see that the graph intersects
and
so what you do is insert the zeros' OPPOCITES into the equation because according to the vertex equation,
that negative in front of
gives you the OPPOCITE outcome, so be careful.
I am joyous to assist you at any time.
Answer:
5.the rental all cost per day is 74-55.5=18.5 per day
Step-by-step explanation:
other questions you have to think seriously
Answer:
g(f(x))= (x+3)(x+3)
Step-by-step explanation:
f(x) =x² + 6x +7
g(x)= x + 2
1st Step: Substitute the x in g(x) =x + 2 by the value of f(x)
g(f(x))= (x² + 6x +7) + 2
g(f(x))= x² + 6x + 9
2nd Step: Simplify
g(f(x))= x² + 6x + 9
g(f(x))= (x+3)(x+3)
Perimeter = 2(width+length) =28
Let x=width of base, then length of base = (28/2)-x = 14-x
Volume of box = length*width*height
=x(14-x)*5 = 5x(14-x)
Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
___
b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
_____
The attached graphs show these to be plausible values for the derivatives at the given points.