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melamori03 [73]
3 years ago
13

Skyler goes to a school which has 1000 students in it. She asks 40 random students whether they like the new 8.30am start to the

day. 30 of them say "no" they do not like it. Use the information to estimate how many students in the whole school dislike the 8.30am start
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

100/40=25

25*30=750

so 750 students would dislike the new starting time.

I really hope this was correct and helpful. I tried my best.

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Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f
olasank [31]

Answer:

\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}

The area of its dilated image EFGH is

\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}

8 0
3 years ago
4c^2-8c-1=0 complete the square round to nearest hundredth
olga55 [171]
Move constant to other side
add 1
4c^2-8c=1
divide by 4 to make leading coeficient 1
c^2-2c=1/4
take 1/2 of linear coeficient and square it
-2/2=-1, (-1)^2=1
add that to both sides
c^2-2c+1=1/4+1
factor perfect squaer and add
(c-1)^2=5/4
square root both sides
c-1=+/-(√5)/2
add 1
c=1+/-(√5)/2

c=2.12 or -0.12
8 0
3 years ago
What value of m makes the system of linear equations mx − y + 3 = 0, (2m − 1)x − y + 4 = 0 have no solution?
Morgarella [4.7K]

Answer:

m ≠1  ( all m in R  except 1 )

Step-by-step explanation:

hello :

mx − y + 3 = 0.....(*)

(2m − 1)x − y + 4 = 0 ....(**)

multiply (*) by : -1       you have :   -mx+y-3=0   ....(***)

                                                    (2m − 1)x − y + 4 = 0 ....(**)

add(***) and(**)  : -mx+ (2m − 1)x+1 =0

(2m-m-1)x+1=0

(m-1)x = -1

this system have no solution  if : m-1≠0   means : m ≠1

6 0
3 years ago
Complete the following exercises by applying polynomial identities to complex numbers. Factor x2 + 64. Check your work. Factor 1
Mumz [18]
x^2+64=x^2-(8i)^2=(x-8i)(x+8i)

16x^2+49=(4x)^2-(7i)^2=(4x-7i)(4x+7i)

(x+9i)^2=x^2+2x\cdot9i+(9i)^2=x^2+18xi+81i^2=x^2+18xi-81=x^2-81+18xi

(x-2i)^2=x^2-2x\cdot2i+(2i)^2=x^2-4xi+4i^2=x^2-4xi-4=x^2-4-4xi

(x+(3+5i))^2=x^2+2x(3+5i)+(3+5i)^2\\\\=x^2+6x+10xi+3^2+2\cdot3\cdot5i+(5i)^2\\\\=x^2+6x+10xi+9+30i+25i^2=x^2+6x+10xi+9+30i-25\\\\=x^2+6x+10xi+30i-16=x^2+6x-16+(10x+30)i


Used:\\i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\\\(a+b)^2=a^2+2ab+b^2
4 0
3 years ago
Read 2 more answers
Find the value of x.
DanielleElmas [232]

Answer:

x = -7

Step-by-step explanation:

Make an equation:

3x + 33 = 12

3x = -21

x = -7

7 0
2 years ago
Read 2 more answers
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