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Lana71 [14]
3 years ago
12

What are the roots of 27x^3=8

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

\bf 27x^3=8\implies x^3=\cfrac{8}{27}\implies x = \sqrt[3]{\cfrac{8}{27}}\implies x = \sqrt[3]{\cfrac{2^3}{3^3}} \\\\\\ x = \cfrac{\sqrt[3]{2^3}}{\sqrt[3]{3^3}}\implies x=\cfrac{2}{3}

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3 years ago
What is the missing constant term in the perfect square that starts with x2 – 16x?
andre [41]

Answer:

64

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the formula being used here is

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4 0
3 years ago
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Sergio [31]

Answer:

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