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Lana71 [14]
3 years ago
12

What are the roots of 27x^3=8

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

\bf 27x^3=8\implies x^3=\cfrac{8}{27}\implies x = \sqrt[3]{\cfrac{8}{27}}\implies x = \sqrt[3]{\cfrac{2^3}{3^3}} \\\\\\ x = \cfrac{\sqrt[3]{2^3}}{\sqrt[3]{3^3}}\implies x=\cfrac{2}{3}

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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

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<u>su</u><u>b</u><u>stituting </u><u>the </u><u>values</u><u> </u><u>in </u><u>the </u><u>formula</u><u> </u><u>,</u>

Volume =  \frac{1}{3}  \times  3.14  \times 9 \times 9 \times 13 \\  \\  \implies \: 1.05 \times 81 \times 13 \\  \\ \implies \: 1105.65 \: mm {}^{3}

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