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2 years ago

Distinguish between the law of conservation of mass and the law of constant proportion

1 answer:

5 0

Laws of conservation of mass - It states that mass can neither created nor destroyed. The total mass before and after a chemical reaction remains constant. Laws of constant proportion - It states that in a chemical substance the elements are always present in a fixed proportion by their mass.

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Limes and lemons have a ph of 2 and are _____. acidic basic bases hydroxides

alexdok [17]

Limes and lemons have a ph of 2 and are acidic.

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3 years ago

A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6

Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

$D=\dfrac{M}{V}$

Where:

D = Density

M = Mass

V = Volume

In your problem we are given:

84 cm³ = volume

760 g = mass

So we just plug in our given into the formula:

$D=\dfrac{M}{V}$

$D=\dfrac{760g}{84cm^{3}}$

$D=9.05g/cm^{3}$

The answer would then be:

9.0 g/cm³

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3 years ago

Where does photosynthesis occur in a plant cell? In what part of a plant cell does photosynthesis occur?

Lynna [10]

Explanation:

In plants, photosynthesis takes place in chloroplasts, which contain the chlorophyll.

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3 years ago

Read 2 more answers

Use the given data at 500 K to calculate ΔG°for the reaction

Anton [14]

Answer : The value of $\Delta G^o$ for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

$2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)$

First we have to calculate the enthalpy of reaction $(\Delta H^o)$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]$

where,

$\Delta H^o$ = enthalpy of reaction = ?

n = number of moles

$\Delta H_f^0$ = standard enthalpy of formation

Now put all the given values in this expression, we get:

$\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]$

$\Delta H^o=-1035.6kJ=-1035600J$

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction $(\Delta S^o)$ .

$\Delta S^o=S_f_{product}-S_f_{reactant}$

$\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]$