Answer: The answer is S = 0.1528 cal/g °C
Explanation:
By the law of conservation of energy, energy is neither created nor destroyed.
So, energy lost by metal pieces is equal to the energy gained by water in the calorimeter.
Specific heat of water is 1 cal/g °C
⇒ heat energy Q = mSΔT, where m = mass of a substance
S = specific heat
ΔT = change in temperature
Now, the heat lost by metal piece, Q = 72×S×(96-31)
= 4680×S cal
Heat gained by water, Q = 130×1×(31-25.5)
= 715 cal
⇒ 4680×S = 715.
⇒ S = 0.1528 cal/g °C.
Let us see the structure of ascorbic acid
As shown there is no COOH group however the OH group can lose a proton and forms conjugate base
The conjugate base formed is stabilized due to resonance
More the stability of conjugate base more the strength of acid
Hence ascorbic acid behaves as an acid
Answer:
Be
Explanation:
Reactivity increases from left to right and decreases from the top of the column to the bottom of column
