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Inessa05 [86]
2 years ago
5

A line passes through the point (-1,-5) and has a slope of -5.

Mathematics
1 answer:
Anna71 [15]2 years ago
5 0
<h3>hello!</h3>

We're given a point that the line intersects and its slope.

Let's use Point-slope:-

\boxed{y-y1=m(x-x1)}

y1 = -5

m=-5

x1=-1

\boxed{y-(-5)=-5(x-(-1)}

\boxed{y+5=-5(x+1)}

Convert to slope-intercept:-

\boxed{y+5=-5x-5}

\boxed{y=-5x-5-5}

Finally,

\bigstar{\boxed{\pmb{y=-5x-10}}

<h3>note:-</h3>

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

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Pachacha [2.7K]
Well, they're saying 9 with an exponet of 2 multiplied by something equals 27..... Hmmm.....
5 0
3 years ago
Helpppp idkkkkk thisssss
Daniel [21]
Yea, it’s 180cm^3

V=bh
V= 20cm • 9cm
V=180cm^3

Have a good day :)
4 0
3 years ago
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
1 year ago
Use the cosine sum and difference identities to find the exact value.<br><br> COS(5pi/12)
nydimaria [60]
5π/12 = (5 · 180°) : 12 = 75°
cos 75° = cos ( 45° + 30° )= cos 45° cos 30° - sin 45° sin 30° =
=√2/2 * √3/2 - √2/2 * 1/2 = \frac{ \sqrt{6} }{4} - \frac{ \sqrt{2} }{4}= \frac{ \sqrt{6} - \sqrt{2} }{4}
=(2.4495 - 1.4142): 4 = 0.258825
8 0
3 years ago
Read 2 more answers
Is (6,7) a solution to the inequality 15x+11y&gt;12
astra-53 [7]

Answer:

(6,7) is a solution

Step-by-step explanation:

To determine if (6,7) is a solution, we substitute the point in and see if the inequality is true

15x+11y>12

15(6) + 11(7) >12

90+77 > 12

167>12

This is true so (6,7) is a solution

8 0
3 years ago
Read 2 more answers
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